3 years ago

For which value of c will the equation 6y−8=c+6y have an infinite number of solutions?

Mathematics

1 answer:

katen-ka-za [31]3 years ago

6 0

Answer:

Step-by-step explanation:

6y - 8 = c + 6y <em>subtract 6y from both sides</em>

6y - 6y - 8 = c + 6y - 6y

-8 = c

The equation has an infinite many solutions if when we get a true equation with no variable y.

Therefore c = -8

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4 years ago

Read 2 more answers

Solve the given equation

AlexFokin [52]

Eliminate the fractions by multiplying by least common multiple.
4,9,12 all go into 36 evenly. Multiply entire equation by 36.

36/4 = 9
36/9 = 4
36/12 = 3

New equation looks like:
$9(w-1) +4(w+1) = -3(w+1) \\ \\ 9w -9 +4w +4 = -3w -3 \\ \\ 9w +4w+3w = -3 +9 -4 \\ \\ 16w = 2 \\ \\ w = \frac{2}{16} = \frac{1}{8}$