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3 years ago

ΔABC has three sides with these lengths: AB = 9, BC = 40, and CA = 41. What is the value of cos C?

Mathematics

1 answer:

Effectus [21]3 years ago

6 0

From the Law of Cosines
Cos (C) = (a^2 + b^2 -c^2) / 2 * a * b
Cos (C) =(40^2 + 41^2 -9^2) / 2 * 40 * 41
Cos (C) = 1,600 + 1,681 - 81 / 3,280
Cos (C) = 3,200 / 3,280
Cos (C) = 0.9756097561 
Incidentally, Angle C = 12.68 Degrees

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Solve B=1/4m(s+z) for s

ElenaW [278]

Answer:

$s = \frac{-mz+4B}{m}$

Step-by-step explanation:

Step 1: Distribute.

$B = \frac{1}{4}m * s + \frac{1}{4}m * z$
$B = \frac{1}{4}ms + \frac{1}{4}mz$
$\frac{1}{4}ms + \frac{1}{4}mz = B$

Step 2: Subtract 1/4(mz) from both sides.

$\frac{1}{4}ms + \frac{1}{4}mz - \frac{1}{4}mz = B - \frac{1}{4}mz$
$\frac{1}{4}ms = -\frac{1}{4}mz + B$

Step 3: Divide both sides by m/4.

$\frac{1}{4}ms/\frac{m}{4}=(\frac{-1}{4}mz + B)/\frac{m}{4}$
$s = \frac{-mz+4B}{m}$

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3 years ago

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raketka [301]

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Andreas93 [3]

Answer:

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Step-by-step explanation:

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