1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Marina CMI [18]
3 years ago
15

Solve pls brainliest

Mathematics
2 answers:
romanna [79]3 years ago
4 0
Its 4in^3
because its cubed
Serga [27]3 years ago
3 0

Answer:

64in

Step-by-step explanation:

v=L×W×H

= 4×4×4

= 16 ×4

= 64in²

You might be interested in
Mario and his family went to the county fair.They bought 2 adult passes.what was the total cost for the family?
joja [24]

<u>Answer:</u>

The total cost for the family was $16

<u>Step-by-step explanation:</u>

Given:

Number of adult tickets = 2

Number of children ticket = 3

To Find:

The total cost of the family = ?

Solution:

The total cost of the family   =  cost for buying 2 adult tickets + cost of buying 3 children tickets

=> 2 \times 5 + 3 \times 2

=> 10 + 6

=> 16

7 0
4 years ago
A player kicks a soccer ball off of the ground. The height of the ball is modeled by the equation h(t)=-\frac34\left(t-4\right)^
Aneli [31]

Answer:

Step-by-step explanation:

We can solve this in either of two approaches:  Mathematically or Graphically.

<u>Mathematically</u>

y=-(3/4)(x-4)^2+12  where y is the height of the ball, and x is the time, in seconds.

We want to know how many seconds for the height to be 0, so y=0.

0 = -(3/4)(x-4)^2+12

-12 = -(3/4)(x-4)^2

12*(4/3) = (x-4)^2

16 = (x-4)^2

x = 8 and 0 (the initial point).]

It will reach the ground in 8 seconds

<u>Graphically</u>

Plot the function and find the time, x, when the graph passes through the x axis (after t = 0).  Attached.

6 0
2 years ago
A radioactive gas with a half-life of 2.4 days accidentally leaks into a room. If the radiation level is now 25% above a safe am
Gnom [1K]
Radioactive half-life is the time it takes for half an amount of radioactive material to decay into something else. In this case, it is assumed that the decay product is not radioactive or otherwise hazardous.

We must use the radioactive decay formula to determine at what time the radiation reaches a safe level.
A = Ao[e^(-0.693)(t)(t 1/2) where t 1/2 is the half-life, t is elapsed time, Ao is the original quantity, A is the future quantity.

We are given a half-life of 2.4 days , an Ao of 1.25 and an A of 1.00:

1.00 = (1.25)e^(-0.693)(2.4)t
1.00/1.25 = e^(-1.6632)t
0.8 = e^(-1.6632)t
t = 0.135 days = 3 hrs 15 min

This is the amount of time to a "safe level" using only radioactive decay, not venting or other means.
8 0
3 years ago
What is the point of this
Ivan

Answer:

B and I are both coplanar

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
You already know I really don’t have to explain myself
Sholpan [36]

Answer:

D

Step-by-step explanation:

3 0
3 years ago
Other questions:
  • Kirk bought songs for his MP3 player. He needed 6 more songs to have a total of 100. Write an integer to represent how many more
    6·2 answers
  • How long will it take Karen to drive 975 miles, if her average speed is 65 miles per hour? how to write a formula
    14·1 answer
  • What is the total length of 5.5 pieces of toy train track that measure 8.5 inches each?
    14·1 answer
  • Please help me solve
    9·1 answer
  • The local deli sells cheese wheels. Each cheese wheel is a cylinder. The height of the cheese wheel is 2.8 inches and the volume
    12·2 answers
  • Solve the equation for all real values of x.<br> cosxtanx - 2 cos x=-1
    6·1 answer
  • 6 + 3x = 2(2 + x)<br><br> What is this answer I need help please anytime soon
    10·1 answer
  • Identify all factors of the expression 18x^2-9x-5
    9·1 answer
  • 3 posters cost $9.60. At this rate how many posters can you buy with $48
    5·1 answer
  • What are the integer solutions to the inequality below? 3 &lt; 3 x − 1 &lt; 2 x + 6
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!