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Answer:
probability of an electric power outage shipboard is 0.075 or 7.5 %
Step-by-step explanation:
Given the data in the question;
Probability of engine malfunction = 25% = 0.25
Probability of generator malfunction = 10% = 0.1
Probability of generator being repaired = 50% = 0.5
probability of an electric power outage shipboard = ?
To get the probability of an electric power outage shipboard, we use the expression;
probability of an electric power outage = 2
× p( Probability of generator malfunction ) × p( Probability of generator being repaired ) × ( 1 - p( Probability of engine malfunction ) )
so we substitute in our given values;
probability of an electric power outage = 2 × 0.1 × 0.5 × ( 1 - 0.25 )
probability of an electric power outage = 2 × 0.1 × 0.5 × 0.75
probability of an electric power outage = 0.075 or 7.5 %
Answer:
.166x + .5 = .5x +.5
Step-by-step explanation:
I need a little more to work with
Answer:
x = <u>16</u> units
Step-by-step explanation:
∆ABC is a 45-45-90 triangle, and ∆BCD is a 30-60-90 triangle.
If side opposite of 90° [∆] = x, side opposite of 45° [∆] = x / √2 = x √ 2 / 2.
Given side AC is opposite of 90° [∆ABC] = 32 √ 2, side opposite of 45° [∆ABC] = 32 √ 2 / √ 2 = 32 which is AB or BC.
Since side BC is part of BCD.
Side opposite of 90° [∆BCD] = BC = 32.
Since x is opposite of 30° [∆BCD].
x = Side opposite of 90° [∆BCD] / 2 = 32 / 2 = 16.