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Hatshy [7]
3 years ago
10

How many solution does the equation have?

Mathematics
2 answers:
never [62]3 years ago
8 0
1 3h+6=36h
   39h+6=h or 1h
IRINA_888 [86]3 years ago
5 0

Answer:

A) 1

Step-by-step explanation:

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How many triangles will be in the 5th set of triangles?
tia_tia [17]

Answer:

25.

Step-by-step explanation:

I am assuming you only mean the small triangles, not the composite ones.

The  second  triangle set has 3 triangles on bottom row and 1 on the top - total 4.

The 3rd triangle set has 5 triangles on the bottom , 3 on the next up and 1 on the top  - total  9

Following the pattern 4th set will have the number of triaNGLES

7 + 5 + 3 + 1 = 16.

So the 5th will have 9 + 7 + 5 + 3 +1 = 25 triangles.

6 0
3 years ago
Susan threw a softball 42 years on her first try and 51 1/3 yard on her second try. How much farther did she throw the softball
Andru [333]

Answer:

28 feet farther than 1st ball.

Step-by-step explanation:

We have been given that Susan threw a softball 42 yards on her first try and 51\frac{1}{3} yard on her second try.

To find second ball is how much farther from the 1st ball, we will subtract 42 yards from 51\frac{1}{3} yards.

\text{The second ball is farther from 1st ball}=51\frac{1}{3}\text{ yards}-42\text{ yards}

\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-42\text{ yards}

Let us have a common denominator.

\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{42*3}{3}\text{ yards}  

\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{126}{3}\text{ yards}

\text{The second ball is farther from 1st ball}=\frac{154-126}{3}\text{ yards}

\text{The second ball is farther from 1st ball}=\frac{28}{3}\text{ yards}

\text{1 yard}=3\text{ feet}

\frac{28}{3}\text{ yards}=\frac{28}{3}\times 3\text{ feet}

\frac{28}{3}\text{ yards}=28\text{ feet}

Therefore, Susan thrown the second ball 28 feet farther from the 1st ball.

7 0
4 years ago
-3y-7x <br> When x=6, y=3
Oksi-84 [34.3K]
-9y-42x

Because they are like terms that is the lowest they can go
4 0
2 years ago
Read 2 more answers
I’m trying to correct this problem but I don’t know how can someone help me
BartSMP [9]

Remark

It is not a straight line distance from the park to the mall. None of the answers give you that result. And if you know what displacement is, none of the answers are really displacement either. The distance is sort of a "as the crow flies." distance. There's a stop off in the middle of town.

Method

You need to use the Pythagorean Formula twice -- once from the park to the city Center and once from the city center to the mall.

Distance from the Park to the city center.

a = 3   [distance east]

b = 4  [distance south]

c = ??

c^2 = 3^2 + 4^2        Take the square root of both sides.

c = sqrt(3^2 + 4^2)

c = sqrt(9 + 16)          Add

c = sqrt(25)

c = 5

So the distance from the park to the city center is 5 miles

Distance from City center to the mall

a = 2 miles [distance east]

b = 2 miles [distance north]

c = ??

c^2 = a^2 + b^2   Substitute

c^2 = 2^2 + 2^2   Expand this.

c^2 = 4 + 4

c^2 = 8             Take the square root of both sides.

sqrt(c^2) = sqrt(8)

c = sqrt(8)          This is the result

c = 2.8

Answer

Total distance = 5 + 2.8 = 7.8

6 0
3 years ago
Geometry question, will give brainiest
Kipish [7]
C. 135
Corresponding parts of congruent figures are the same
7 0
3 years ago
Read 2 more answers
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