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mash [69]
3 years ago
10

A student factors 10x^2+3x-27 to the following. (2x-3)(5x+9)

Mathematics
2 answers:
bearhunter [10]3 years ago
8 0

Answer:

A

Step-by-step explanation:

The form (2x-3)(5x+9) is fully factored. To determine if it is equivalent, multiply the parenthesis out.

(2x-3)(5x+9) = 10x² - 15x + 18x - 27 = 10x² + 3x - 27

Yes this is equivalent.

The solution is A.

Aleonysh [2.5K]3 years ago
7 0

Answer:

Option A - The expression is equivalent, but it is completely factored

Step-by-step explanation:

Given : A student factors 10x^2+3x-27 to the following (2x-3)(5x+9).

To find : Which statement is true about (2x-3)(5x+9) is true?

Solution :

First we are factoring the given quadratic equation,

10x^2+3x-27=0

Applying middle term split,

10x^2+18x-15x-27=0

2x(5x+9)-3(5x+9)=0

(2x-3)(5x+9)=0

We have seen that the expression is completely factored and equivalent to given factor.

Therefore,Option A is correct.

The expression is equivalent, but it is completely factored.

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find the two angles measures from the diagram 7x+9 5x+3 there's 3 answers 1. 73 and 73 2. 107 ,107 3.107 and 73 this is so confu
viva [34]

Answer:

<h2>107 and 73</h2><h2 />

Step-by-step explanation:

supplementary angle

7x + 9 + 5x + 3 = 180

12x = 180 - 3 - 9

x = 168 / 12

x = 14

plugin x=14 into the equation

= 7x + 9

= 7(14) + 9

= 107°

plugin x=14 into the equation

= 5x + 3

= 5(14) + 3

= 73°

4 0
3 years ago
IM CONFUSED PLEASE HELP! THANK YOU!
11111nata11111 [884]

Answer:

Hope This Help If Not Sorry

Step-by-step explanation:

minimum  In mathematical analysis, the maxima and minima of a function, known collectively as extrema, are the largest and smallest value of the function, either within a given range, or on the entire domain.

7 0
3 years ago
Read 2 more answers
Cameron bought a packet of 45 bars of chocolate.He ate one fifth of them on Tuesday.He ate a twelfth of the remaining bars on We
Vlad1618 [11]
He bought 45 bars of chocolate.

1/5 x 45 = 9 
He ate 9 bars on Tuesday.

45 - 9 = 36
He had 36 bars left.

1/12 x 36 = 3
He ate 3 bars on Wednesday

36 - 3 = 33
He had 33 bars left.

------------------------------------------------
Answer: He had 33 bars left.
------------------------------------------------
6 0
3 years ago
Read 2 more answers
Jim needs to mix a medication with water to make the appropriate solution. The medications says to mix 3 oz of medication with 5
skelet666 [1.2K]

Answer:

38 or 38.33 cups of water.

Step-by-step explanation:

You need 5 cups of water for every 3 ounces of medication. We can set up a proportion: #oz of medication/#cups of water= #oz of medication/# cups of water. We can plug in some numbers from the problem.

3/5=23/n. You can use any variable, but I'm using n for how many cups of water Jim will need for 23 ounces of medication.

We can cross multiply: 3*n=5*23.

3n=115

We divide both sides by 3.

n=38.3333333.......

Rounding to the nearest whole number, Jim will need 38 cups of water, or 38.33 cups if you're rounding to the nearest hundredth.

Hope this helps :)

6 0
3 years ago
On a certain hot​ summer's day, 391 people used the public swimming pool. The daily prices are $1.25 for children and $2.25 for
igomit [66]

Number of adults = 264

Number of children= 127

Step-by-step explanation:

Let the number of adults be......x

Let the number of children be.....y

The total number of people that used the public swimming pool is given as 391. This means

x+y=391

The total cost per the receipt is : $752.75

This means, 2.25 x+ 1.25 y = 752.75

The two equations are;

x+y=391  ...........(i)

2.25 x+ 1.25 y = 752.75...........(ii)

Making the x variable equal to eliminate x

2.25x + 2.25 y = 879.75

2.25x + 1.25 y = 752.75

Apply subtraction as

1.00 y = 127.00

y=127

Use the value of y in equation (i)

x+y=391

x+127=391

x=391-127=264

Number of adults = 264

Number of children= 127

Learn More

Simultaneous equations: brainly.com/question/12318095

Keywords ; public, swiming pool, prices, daily, adults, children, receipt, admission

#LearnwithBrainly

7 0
3 years ago
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