3 years ago

-5x+y=-3

1 answer:

5 0

(3)(-5x+y=-3)
(5)(3x-8y=24)

-15x+3y=-9
15x-40y=120

3y=-9
-40y=120

-37y=111
Divide both sides by -37

y=-3

To solve for x. Choose one equation from the given and plug what you get in Y.

I'll choose, -5x+y=-3
So, -5x+(-3)=-3
-5x=0
Divide both sides by -5
x=0/-5

Hope, this helps.

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The diagram shows the rectangle ABCD, where A is (3,2) and B is (1,6).

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(i)
$A(3,2),B(1,6)
\\
\\m_{AB}= \frac{6-2}{1-3}=-2
\\
\\m_{BC}m_{AB}=-1
\\ 
\\m_{BC}= \frac{-1}{m_{AB}} = \frac{-1}{-2}= \frac{1}{2} 
\\
\\B(1,6)\Rightarrow x_1=1,y_1=6
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\\BC:y-y_1=m_{BC}(x-x_1)
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\\
\\C=AC\cap BC
\\
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(iii)
$A(3,2)B(1,6),C(13,12)
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\\
\\d(A,B)= \sqrt{(1-3)^2+(6-2)^2}= \sqrt{20} =2 \sqrt{5} 
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\\d(B,C)= \sqrt{(13-1)^2+(12-6)^2}= \sqrt{180}= 6\sqrt{5} 
\\ 
\\P=2(2 \sqrt{5}+6 \sqrt{5})=2\times8 \sqrt{5} =16 \sqrt{5}$

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