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sladkih [1.3K]
3 years ago
13

Solve 12x^2+4x-3=0 by completing the square.

Mathematics
1 answer:
vazorg [7]3 years ago
8 0

Answer:

12(x+1/6)^2-3=0

Step-by-step explanation:

12x^2+4x-3=0

12(x^2+1/3x)-3=0

12(x+1/6)^2-3=0

Hoped this helped,

JoeLouis

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