Solve 12x^2+4x-3=0 by completing the square.
1 answer:
Answer:
12(x+1/6)^2-3=0
Step-by-step explanation:
12x^2+4x-3=0
12(x^2+1/3x)-3=0
12(x+1/6)^2-3=0
Hoped this helped,
JoeLouis
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