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navik [9.2K]
3 years ago
7

How do I solve for A?

Mathematics
1 answer:
Gwar [14]3 years ago
5 0

*Have to make sure the square root is around the whole problem

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Pamela and Debbie are shelving books at a public library. Pamela shelves 26 books at a time, whereas Debbie shelves 7 at a time.
Ira Lisetskai [31]

If both Pamela and Debbie can shelf the same number of books at the end, the smallest number of books each could have shelved is 182

The number of books that Pamela can shelf at a time = 26

The number of books that Debbie can shelf at a time = 7

If both Pamela and Debbie can shelf the same number of books at the end, the smallest number of books each could have shelved is the least common multiple of 26 and 7

The Least common multiple of 26 and 7  = 182

Therefore, if both Pamela and Debbie can shelf the same number of books at the end, the smallest number of books each could have shelved is 182

Learn more on Least Common Multiple here: brainly.com/question/363238

8 0
2 years ago
The solution set to 6 + 2n > 12 is n > 3. Which are the correct representations of this solution? Select two options.
Alina [70]

The correct representation of 6 + 2n > 12 (n > 3) is  (3, ∞) and a number line with an open circle at +3 and being shaded from +3 to +5.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Given the equation::

6 + 2n > 12

Subtracting 6 from both sides:

6 + 2n - 6 > 12 - 6

2n > 6

Dividing by 2:

n > 3

The correct representation of 6 + 2n > 12 (n > 3) is  (3, ∞) and a number line with an open circle at +3 and being shaded from +3 to +5.

Find out more on equation at: brainly.com/question/2972832

#SPJ1

3 0
1 year ago
The following set of coordinates represent which figure (1,1) (5,3) (7,7) (3,5)
igomit [66]

Answer:

It should be a rhombus :)

4 0
2 years ago
A 4 pack of jump ropes costs $15.28. What is the unit price? per jump rope​
babymother [125]

Answer:

Each jump rope will cost: $15.28 ÷ 4 = $3.82

3 0
3 years ago
If Carbon Monoxide had a concentration in the air of 0.000518% how many particles out of 331,002,651 would be Carbon Monoxide?
Alex17521 [72]

Answer:

171,459 particles of CO

Step-by-step explanation:

331,002,651×0.000518 = 171459

5 0
3 years ago
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