Urn 1 = 4 green balls and 6 blue balls, a total of 10 balls
Urn 2 = 6 green balls and 2 blue balls, a total of 8 balls.
Probability of blue balls:
Urn 1 : P = 6/10
Urn 2 : P = 2/8
Probability that both balls are blue:
6/10 * 2/8 = 6*2 / 10*8 = 12/80 = 6/40 = 3/20
Answer is B. 3/20
constant cost of 12
$1 for rides.
the number of rides you take is unknown, x
so its f(x) = 1x +12 or x+12
so if you rode 20 rides its
f(20) = 20+ 12 =32
You square it so for example the first one would be 1
