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2 years ago

Find the area of the triangle

Mathematics

1 answer:

olchik [2.2K]2 years ago

6 0

Answer:

4.5

Step-by-step explanation:

1/2 times base times height

( Area of a triangle )

1/2(3)(3)

=4.5

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Which of the following is the number if sides a polygon can have to form a regular tessallation?

Arisa [49]

None of the options is true.

Three Different, Regular tessellation is formed 1. if we join regular polygons of side 3, called equilateral triangle,2. Regular polygon of side 4, called Square, and 3. Regular polygon of side,6 called hexagon,

to form a pattern.

<h3>What is the polygon?</h3>

A polygon is said to be regular if all interior angles and all sides are equal.

The regular polygon of side 3, when joined together can be named: 3.3.3.

The regular polygon of side 4, when joined together can be named 4.4.4.

The regular polygon of side 6, when joined together can be named 6.6.6.

So, a regular tessellation is formed, from a regular polygon having,3,4, and 6 Sides.

None of the sides of the polygon, which is given in the option, can be used to form a regular tessellation.

None of the options is true.

To learn more about the polygon visit:

brainly.com/question/1592456

#SPJ1

6 0

2 years ago

$5,000 is invested at 3% interest.

adell [148]

5000*0.03+0.05x=275
Solve for x
X=2500
The answer is b

4 0

3 years ago

Read 2 more answers

How is 3 divided by 1.4 ...2.14? Working please!

musickatia [10]

Turn 1.4 into a whole number. Which makes 1.4 to 14. We know that 3 has a decimal point at the end. So move the decimal point of 3 to the right, making it 30. Now do 30/14. You will get...

30/14 = 2.14

GG ;)

5 0

3 years ago

Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate

kolbaska11 [484]

Answer:

You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality $x^{2}-5x+4\leq 0$ . To do that, factorize, then we have that $(x-4)(x-1)\leq 0$ . This implies that

$x-1\leq 0\, \text{and}\, x-4\geq 0$

$x-1 \geq 0\, \text{and}\, x-4\leq 0$

In the first case the solution is the empty set $\emptyset$ . In the second case the solution is the interval $1\leq x \leq 4$ . Now we have that

$A=[1,4]$

$B=(3,5)$

$C=(3,4]$ .

To show that $A\cap B\subseteq C$ consider $x\in A\cap B$ . Then $1\leq x \leq 4\, \text{and}\, 1$ , this implies that $3$ , then $x\in C$ . Now, to show that $C\subseteq A\cap B$ consider $x\in C$ , then $3$ , then $1\leq x \leq 4\, \text{and}\, 3$ , then $x\in [1,4] \, \text{and}\, x\in (3,5)$ , this implies that $x\in A\cap B$ .

Observe the image below.

7 0

3 years ago

Dennis is going to use a number line to multiply 6 × 4.

Sergeeva-Olga [200]

B. The answer will always be to the right of 4.
6 x 4 = 24
24 is greater than 4, which means it is to the right of 4. On a number line, numbers increase from left to right.

8 0

3 years ago

Read 2 more answers