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chubhunter [2.5K]
2 years ago
10

Help with question #10

Mathematics
2 answers:
Tanzania [10]2 years ago
5 0
Because the line are parrel so 5x+10=x+100
x=25
25+100=125
MAXImum [283]2 years ago
4 0
The answer is x=25 hope this helps :)
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Trip has 15 coins worth 95 cents.Four of the coins are each worth twice as much as the rest. Construct a math argument to justif
const2013 [10]
(11*5)+(4*10)=95
11+4=15
Both are equal to the constraints of the word problem and there for justified.
6 0
3 years ago
Do problem 6 show work i will give brainliest if ur correct.
aliina [53]

Step-by-step explanation:

they forget the last step which is to take the square root of the sum

7) a = 4

b = 17

a² + b² = c²

4²+ 17² = c²

16 + 289 = c²

305 = c²

√305 = c

17.464249196572980 = C

7 0
3 years ago
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Naily [24]

The answer is C... Hope it helps

4 0
3 years ago
Suppose two $20 bills, three $10 bills, one $5 bill, and seven $1 bills are placed in a bag. If you were to pull a bill at rando
Korolek [52]

Answer:

Assuming that the $1 bill was pulled at random, then the expected value of the amount chosen is \frac{7}{13}.

Step-by-step explanation:

From the given question, the bag contains;

$1 bill = 7

$5 bill = 1

$10 bill = 3

$20 bill = 2

Total number of bills in the bag = 13

Pulling a bill at random, the bills would have an expected value as follows:

For $1 bill, the expected value = \frac{7}{13}

For $5 bill, expected value = \frac{1}{13}

For $10 bill, expected value = \frac{3}{13}

For $20 bill, the expected value = \frac{2}{13}

Assuming that the $1 bill was pulled at random, then the expected value of the amount chosen is \frac{7}{13}.

6 0
3 years ago
Use the points in the diagram to name the figure.
Viefleur [7K]

D) Line JK

<----->

JK

<em>H</em><em>o</em><em>pe </em><em>it </em><em>helps </em><em>:</em><em>)</em>

3 0
1 year ago
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