Answer:
These triangles cannot be proved congruent
Step-by-step explanation:
The theorems for congruence are SSS SAS ASA AAS. Here, there is only one common side and one common angle marked, therefore you cannot prove congruency.
Answer:
Let the breadth is x, then the length is 3x.
<u>The area is:</u>
<u>The breadth is decreased by 2 m: </u>
<u>The length is increased by 4m: </u>
<u>The area is now:</u>
- (x - 2)(3x + 4) = 3x² - 1/3(3x²)
- 3x² + 4x - 6x - 8 = 2x²
- x² - 2x - 8 = 0
- x² - 2x + 1 = 9
- (x - 1)² = 3²
- x - 1 = 3
- x = 4
The breadth was 4 m and the length 12 m
The correct answer is:
[C]: "

" .
____________________________________________________Explanation:____________________________________________________Given:
____________________________________________________ 2 / (9x) = 4 / 7 ; solve for "x" ;
____________________________________________________Cross-multiply:
→ (9x)*4 = 2 * 7 ;
→ 36x = 14 ;
Divide each side of the equation by "36" ;
to isolate "x" on one side of the equation; & to solve for "x" ;
→ 36x / 36 = 14 / 36 ;
x = 14/ 36 ;
→ x = 14/36 = (14÷2) / (36÷2) = 7/18 ;
______________________________________________________
The answer is: "

" ;
→ which is:
Answer choice: [C]: "

" .
______________________________________________________
Answer:
5 3/5
Step-by-step explanation:
Convert 1/8 to 10/80 and 7/10 to 56/80 56/10= 5 3/5