A bus as speed of 20m/s begin to slow at constant acceleration of 8.00m/s2 along a straight line find the average speed for the
5al.s interv
1 answer:
Answer:
-20 m/s.
Step-by-step explanation:
The computation of the average speed is shown below:
Given that
The initial velocity of the bus, u = 20 m/s
Aceleration of the bus, -a = 8 m/s²
time of motion, t = 5 s
Now The final velocity of the bus is
v = u + at
v = 20 + (-8 × 5)
v = 20 - 40
v = -20 m/s.
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so think of it as a interger
Let x be the speed.
Maximum is 65 so x needs to be less than or equal to 65.
The minimum is 45, so x also has to be greater than or equal to 45
45 <= x => 65
I’m not sure I understand your question
X=12 because 3 times 12 equals 36. if you divide by 3 on both sides you would be left with that
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