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zhannawk [14.2K]
3 years ago
10

A bus as speed of 20m/s begin to slow at constant acceleration of 8.00m/s2 along a straight line find the average speed for the

5al.s interv
Mathematics
1 answer:
MrRissso [65]3 years ago
6 0

Answer:

-20 m/s.

Step-by-step explanation:

The computation of the average speed is shown below:

Given that

The initial velocity of the bus, u = 20 m/s

Aceleration of the bus, -a = 8 m/s²

time of motion, t = 5 s

Now The final velocity of the bus is  

v = u + at

v = 20 + (-8 × 5)

v = 20 - 40

v = -20 m/s.

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Llana [10]

Option A: drop of 8 meters would be correct because a drop in this case indicates something has been removed. -8 equals 8 below 0.

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3 years ago
How do I prove exterior angle theorem
soldier1979 [14.2K]
The measure of an exterior angle of a triangle is equal to the sum of the measures of the two non-adjacent interior angles of the triangle.


m∠4=m∠1+m∠2m∠4=m∠1+m∠2
Proof:
Given: ΔPQRΔPQR
To Prove: m∠4=m∠1+m∠2m∠4=m∠1+m∠2
StatementReason1ΔPQRΔPQR is a triangleGiven2m∠1+m∠2+m∠3=180°m∠1+m∠2+m∠3=180°Triangle Sum Theorem3∠3∠3 and ∠4∠4 form a linear pairDefinition of linear pair.4∠3∠3 and ∠4∠4 are supplementaryIf two angles form a linear pair, they are supplementary.5m∠3+m∠4=180°m∠3+m∠4=180°Definition of supplementary angles.6m∠3+m∠4=m∠1+m∠2+m∠3m∠3+m∠4=m∠1+m∠2+m∠3Statements 2, 5 and Substitution Property.7m∠4=m∠1+m∠2m∠4=m∠1+m∠2Subtraction Property.   im 99.9 perecent sure this is right bc im only in middle school but hope it helps
5 0
3 years ago
Find the radius of convergence of the power series. (if you need to use or –, enter infinity or –infinity, respectively. ) [infi
Alona [7]

For given power series \sum_{n=0}^{\infty} \frac{(-1)^nx^n}{2^n} the radius of convergence is 2.

For given question,

We have been given a power series \sum_{n=0}^{\infty} \frac{(-1)^nx^n}{2^n}

We need to find the radius of convergence of the power series.

We use ratio test to find the radius of convergence of the power series.

Let a_n=\frac{(-1)^nx^n}{2^n}

\Rightarrow a_{n+1}=\frac{(-1)^{n+1}x^{n+1}}{2^{n+1}}

Consider,

\lim_{n \to \infty}|\frac{a_{n+1}}{a_n} |\\\\= \lim_{n \to \infty} |\frac{\frac{(-1)^{n+1}x^{n+1}}{2^{n+1}}}{ \frac{(-1)^nx^n}{2^n} } |\\\\=\lim_{n \to \infty} |\frac{(-1)^{n+1}x^{n+1}}{2^{n+1}}\times \frac{2^n}{(-1)^nx^n} |\\\\=\lim_{n \to \infty} |\frac{(-1)x}{2} |\\\\=\lim_{n \to \infty}|\frac{-x}{2} |\\\\=\frac{x}{2}

By Ratio test, given power series converges at |\frac{x}{2} | < 1

⇒ |x| < 2

So, the radius of convergence is 2.

Therefore, for given power series \sum_{n=0}^{\infty} \frac{(-1)^nx^n}{2^n} the radius of convergence is 2.

Learn more about the radius of convergence here:

brainly.com/question/2289050

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8 0
2 years ago
Let ∠D be an acute angle such that cosD=0.33. Use a calculator to approximate the measure of ∠D to the nearest tenth of a degree
Gelneren [198K]

Answer:

70.7 degrees

Step-by-step explanation:

6 0
3 years ago
76763476-2345-345-324-23+5324+345234÷6847397475287365x3789127482297547 85345455345325234-345325+32453892727-25666634872962365823
Nadusha1986 [10]

Answer:

−1.43000372×10^{29}

Step-by-step explanation:

76763476-2345-345-324-23+5324+345234÷6847397475287365x3789127482297547 85345455345325234-345325+32453892727-2566663487296236582345x54287395 79238365379245÷97438528453492= what

76763476-2345-345-324-23+5324+(1.91041289x10^{22})-345325+32453892727-(1.43000391x10^{29})

76765763+(1.91041289x10^{22})-345325+32453892727-(1.43000391x10^{29})

−1.43000372×10^{29}

4 0
3 years ago
Read 2 more answers
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