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4 years ago

If the sequence 1, 6, 7, 13, 20, ... were to follow the same pattern as the Fibonacci sequence, what are the next three terms?

1 answer:

3 0

The Fibonacci sequence is generated by starting with the numbers 0 and 1 (or 1 and 1) and obtaining the next number by adding them together. All successive numbers are the sum of the previous two.

0 + 1 = 1

1 + 1 = 2

1 + 2 = 3

2 + 3 = 5

and so on.

For this sequence, we have

1 + 6 = 7

6 + 7 = 13

7 + 13 = 20

13 + 20 = 33

20 + 33 = 53

33 + 53 = 86

You might be interested in

What is -42.15+12.45

JulsSmile [24]

-42.15+12.45=-30...............................

3 0

3 years ago

Read 2 more answers

Which is the best estimate of the capacity of a bathtub? A. 5 milliliters B. 50 milliliters c. 5 liters D. 50 liters

Murrr4er [49]

Answer:

D 50 liters

Step-by-step explanation:

mL is really small amount so it not A or B. 5 L is like 5 bottles which wont fill it up much so lets take out C. the answer left out is D 50 L which is the answer

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3 years ago

Assume that females have pulse rates that are normally distributed with a mean of mu equals 72.0 beats per minute and a standard

larisa86 [58]

Answer:

a) 36.88% probability that her pulse rate is between 66 beats per minute and 78 beats per minute

b) 66.30% probability that they have pulse rates with a mean between 66 beats per minute and 78 beats per minute

Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n of at least 30 can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 72, \sigma = 6.5$

a. If 1 adult female is randomly selected, find the probability that her pulse rate is between 66 beats per minute and 78 beats per minute.

The probability is?

This is the pvalue of Z when X = 78 subtracted by the pvalue of Z when X = 66. So

X = 78

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{78 - 72}{12.5}$

$Z = 0.48$

$Z = 0.48$ has a pvalue of 0.6844

X = 66

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{66 - 72}{12.5}$

$Z = -0.48$

$Z = -0.48$ has a pvalue of 0.3156

0.6844 - 0.3156 = 0.3688

36.88% probability that her pulse rate is between 66 beats per minute and 78 beats per minute

b. If 4 adult females are randomly selected, find the probability that they have pulse rates with a mean between 66 beats per minute and 78 beats per minute

The probability is?

Now we have $n = 4, s = \frac{12.5}{\sqrt{4}} = 6.25$

X = 78

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{78 - 72}{6.25}$

$Z = 0.96$

$Z = 0.96$ has a pvalue of 0.8315

X = 66

$Z = \frac{X - \mu}{s}$

$Z = \frac{66 - 72}{6.25}$

$Z = -0.96$

$Z = -0.96$ has a pvalue of 0.1685

0.8315 - 0.1685 = 0.6630

66.30% probability that they have pulse rates with a mean between 66 beats per minute and 78 beats per minute

c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30?

The condition for the sample size exceeding 30 is when the population is skewed. If it is normally distributed, the size is not a condition.

So the correct answer is:

Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size.

3 0

3 years ago

Read 2 more answers

How many ways are there to move from one corner of a cube to the diagonally opposite corner, in three moves, each of which trave

Ulleksa [173]

Answer: 6 ways

there are 6 ways to move from one corner of a cube to the diagonally opposite corner in three moves

Step-by-step explanation:

Given that;

-It's restricted to three moves.

-It has to move from one diagonal to its opposite diagonal.

-it can only move through the edges.

Hence, in the first move.

We have three(3) different options that is three different possible moves that can lead us to the final destination.

The second move.

We have two (2) different possible moves each

The last move

We have just one(1) possible move.

To get the total possible ways, we will multiply the possible options for each move.

Move 1 = 3 options

Move 2 = 2 options each

Move 3 = 1 option each

3 × 2 × 1 = 6 ways

6 0

4 years ago

How do you solve these 3?

Murljashka [212]

Answer:

1)2.83

2)-5.74

3)4.16

I hope this help

8 0

3 years ago