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OLEGan [10]
3 years ago
15

Can someone help me please

Mathematics
1 answer:
goldenfox [79]3 years ago
7 0

Answer:

1. \quad\dfrac{1}{k^{\frac{2}{3}}}\\\\2. \quad\sqrt[7]{x^5}\\\\3. \quad\dfrac{1}{\sqrt[5]{y^2}}

Step-by-step explanation:

The applicable rule is ...

  x^{\frac{m}{n}}=\sqrt[n]{x^m}

It works both ways, going from radicals to frational exponents and vice versa.

The particular power or root involved can be in either the numerator or the denominator. The transformation applies to the portion of the expression that is the power or root.

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Please help ASAP I don’t understand
madreJ [45]

Answer:

88 square inches

Step-by-step explanation:

if the entire square was shaded it would be 14 x 12  (as best as i can see)

the "cut out" or white part of the square is 8 x 10

Entire squre - cutout white part

14 x 12     -  8 x 10

168 - 80

88 sq in

4 0
3 years ago
Which expression is equivalent to [(2a-3b4)2(3a5b)-2]-1 ? Assume a =/ 0, b =/ 0
zubka84 [21]

Answer: The Third option

Step-by-step explanation:

1/36a^4b^10

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2 years ago
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2 years ago
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6 0
3 years ago
Help me plz I’m struggling with this
elena-s [515]

Answer:

AC = 8√3       AC = 7.65          

A = 43.17°       AB = 16.8

B = 46.83°      B = 27°

Step-by-step explanation:

FIRST TRIANGLE

by using pythagorus theorem:

Hypo² = Base² + height²

19² = 13² + AC²

AC² = 19² - 13²

AC² = 192

AC = √192

AC = 8√3

sinФ =base/hypo

sin A = 13/19

A = sin^-1 (13/19)

A = 43.17°

43.17°+ B + 90° =180 (sum of angles of triangle)

B = 180° - 133.17°

  = 46.83°

<h3>SECOND TRIANGLE</h3>

TanФ = base/height

Tan 63° = 15 / AC

1.96 = 15/AC

AC = 15/1.96

AC = 7.65

AB² = AC² + BC²

AB² = 7.65² + 15²

AB² = 283.5

AB = √283.5

AB = 16.8

tan B = AC /BC

tanФ = 7.65/15

tanФ = 0.51

Ф = tan^-1(0.51)

B = 27°

3 0
3 years ago
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