Answer:
The length of the DNA of the Neisseria gonorrhoeae is 2220 kbps. It is to be noted that 1 kbp = 1000 bases. After converting the kbps into base pairs we get:
2200 * 1000 = 2220000 base pairs
The entire length of the base pairs is,
2220000 * 0.34 nm = 754800 nm
After converting it into centimeters we get:
754800 * 10^-7 = 0.7548 cm
Therefore, the total length of the molecule of DNA is 0.7548 cm.
The 85 percent of the 2220000 base pairs = 2220000 * 85 / 100
= 188700000 / 100 = 1887000 base pairs
Each of the amino acid is encrypted by three base pairs (triplet codon)
Thus, the number of bases needed to generate a protein with 300 amino acids is 300 * 3 = 900 base pairs
The number of protein encoding genes in N. gonorrhoeae genome is :
= 1887000 / 900 = 2096.6 or 2097
Hence, the total number of protein encoding genes present in the genome of N. gonorrhoeae is 2097.
The left 15 percent genes can be considered as the non-coding genes. They exhibit the information essential to monitor the expression of the 85 percent genes.
