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3 years ago

What are some of the roles of proteins in the human body?

1 answer:

3 0

Hopes this helps:

Answer:

Proteins has many roles in your body. It helps repair and build your body’s tissues, allows metabolic reactions take place and coordinates bodily functions. In addition to providing your body with a structural framework, proteins also maintain proper pH and fluid balance.

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What 2 processes cause hurricanes?

Zielflug [23.3K]

Explanation:Warm air and warm water combine to create and drive destructive storms. The two essential ingredients in every hurricane are warm water and moist, warm air.

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2 years ago

After soaking the gummy bear in water overnight, you observed that the gummy bear in the tap water increased in size. Which stat

Bas_tet [7]

<span>A. Water is moving into the gummy bear because the concentration of water molecules inside the gummy bear is lower than outside.
</span>

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3 years ago

How is punctuated equilibrium different from gradualism?

Anit [1.1K]

For Gradualism, changes in species is slow and gradual, occurring in small periodic changes in the gene pool, whereas for Punctuated Equilibrium, evolution occurs in spurts of relatively rapid change with long periods of non-change

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3 years ago

A cross is made between homozygous wild-type female Drosophila (a^+ a^+ b^+ b^+ c^+ c^+) and triple-mutant males (aa bb cc) (the

marusya05 [52]

Answer:

a is the middle gene.

Distance [b-a]= 24.7 mu

Distance [a-c]= 15.8 mu

Distance [b-a} = 40.5 mu

Explanation:

A homozygous wild-type female drosophila (a⁺b⁺c⁺/a⁺b⁺c⁺) is crossed with a homozygous recessive male (abc/abc). <u>The order of the genes here is arbitrary. </u>

The F1 is heterozygous for the three genes (a⁺b⁺c⁺/abc). The F1 females were test crossed (crossed with abc/abc males).

The F2 shows the following phenotypic ratios:

320 a⁺b⁺c⁺
308 a b c
102 a⁺ b c⁺
112 a b⁺ c
66 a⁺ b⁺ c
59 a b c⁺
18 a⁺ b c
15 a b⁺ c⁺

Total = 1000

The male parent is homozygous recessive for the 3 genes, so the observed phenotypes of the offspring correspond to the gametes received from the mother.

Recombination during meiosis is a rare event, so the most abundant gametes are always the parentals: a⁺b⁺c⁺ and abc.

The least abundant gametes, following the same logic, are the double crossovers (DCO): a⁺bc and ab⁺c⁺.

<h3><u>1st. Determine the gene order</u></h3>

Compare the parental and the DCO gametes. The allele that is switched corresponds to the middle gene. In this case, gene a is in the middle of the other two.

<h3><u>2nd Determine the single crossover gametes</u></h3>

The F1 mother that generated all 8 types of gametes had the genotype b⁺a⁺c⁺/bac (correct order of genes).

The single crossover (SCO) gametes resulting from recombination between genes b and a are b⁺ac and ba⁺c⁺.
The single crossover (SCO) gametes resulting from recombination between genes a and c are b⁺a⁺c and bac⁺.

<h3><u>3) Calculate the recombination frequencies between genes </u></h3>

Recombination frequency (RF) = #Recombinants/Total progeny

RF [b-a]= (102+112+18+15)/1000= 0.247
RF [f-br]= (66+59+18+15)/1000= 0.158

<h3><u /></h3><h3><u>4) Calculate the distance in map units </u></h3>

Distance (mu) = RF x 100

Distance [b-a]= 0.247 × 100 = 24.7 mu

Distance [a-c]= 0.158 × 100 = 15.8 mu

Distance [b-a} = 24.7 mu + 15.8 mu = 40.5 mu

<h3><u>The gene map therefore looks like: </u></h3>

b------------24.7 mu--------------------------a---------15.8 mu-----------c

4 0

3 years ago

Will mark brainliest!

saw5 [17]

Answer: The combination produced is RRtt.

The combination rrTt does not appear in this punnett square.

Explanation:

As the problem does not indicate more information, I assume that punnett square is made between two RRtt genotypes. It can produce gametes that have the alleles Rt. A gamete is a sexual cell (egg or sperm) that has only one allele of each gene. And, each gamete codes for a different gene. Since here we have two different types of alleles (R and t), it is a dihybrid cross.

<u>A Punnett square is a diagram used to predict the genotypes of a cross or breeding experiment.</u> It is used to determine the genotypes and phenotypes of the offspring. To do it, you have to label the rows with one parent's gametes and label the columns with the other parent's genotype. Then, have each box inherit letters from its row and column, and interpret the results.

Then, the punnett square (shown in the picture) will be between RRtt and RRtt whose gametes can only be Rt, so Rt x Rt will be made.

The result in an offspring which will be 100% RRtt, and there is no rrTt combination here because non of the parents have an r allele, then none of the children can inherit it.

To have an offspring where rrTt genotype is shown, a different genotype must be used, in which both parents must have at least one r allele and one t allele. For example, it could be Rrtt x rrTt.

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2 years ago