Question

A time standard was set as 0.20 hour per unit based on the 20th unit produced. Assume the task has a 60 percent learning curve. Refer to Exhibit 6.4. What would be the expected time of the 40th, 80th, and 160th units? (Do not round intermediate calculations. Round your answers to 2 decimal places.)

Answer 1

Answer:

40th unit = 0.11 hr

80th unit = 0.06 hr

160th unit = 0.03 hr

Explanation:

Given :

$T_{20} = 0.2$

Learning rate = 60% = 0.6 (r)

Now using the learning curve equation,

$T_n = T_1(n)^b$

where b is  $b= \frac{\ln r}{\ln 2} = \frac{\ln 0.6}{\ln 2}$  = -0.833

Now

$T_{20} = T_1(20)^{-0.833}$

$0.20 = T_1 (0.0824)$

$T_1$ = 2.5

For 40th unit

$T_{40} = 2.5(40)^{-0.833}$

      = 0.11 hrs

For 80th unit

$T_{80} = 2.5(80)^{-0.833}$

      = 0.06 hrs

For 160th unit

$T_{160} = 2.5(160)^{-0.833}$

        = 0.03 hr