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xenn [34]
3 years ago
9

What is 1⁄5 × 4⁄7 × 3⁄4

Mathematics
2 answers:
Anna71 [15]3 years ago
3 0

Answer:

3/35

Step-by-step explanation:

to solve this expression 1⁄5 × 4⁄7 × 3⁄4

solution

1⁄5 × 4⁄7 × 3⁄4

= 1 x 4 x 3/5 x 7 x 4

= 12/140

= 6/70

= 3/35

777dan777 [17]3 years ago
3 0

Answer:0.08571

Step-by-step explanation:

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ankoles [38]
In geometry, "construct" means do it with a straightedge (not a ruler) and compass.

Here's how you do it:

1. Using the straightedge, draw a line clearly longer than segment RS.

2. Place a dot at one end of the line you drew.

3. Stick the "center" of your compass in the R position of the RS segment.

4. Open the compass so the pencil point passes through the S position. Your compass now marks off segment RS.

5. Without opening or closing the compass, pick it up and stick the center into the dot you made on your new line.

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7. Place a dot where the hash mark crosses the line. The segment on the new line between the two dots is a segment congruent to RS.

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4 0
4 years ago
-7- 2x² - 6 = −2x² + 1<br> First Step:<br> 13- 2x² = 2x² + 1<br> What property is this
lorasvet [3.4K]

Answer:

Combine like terms, although the provided answer is missing a "-" sign in front of the "13."  

Step-by-step explanation:

Combine like terms.  The -7 and -6 can be added to produce -13.

The correct result is <u>-</u>13 - 2x^2 = <u>-</u>2x^2 + 1  [Not _13- 2x² = _2x² + 1

Perhpas the initial equation is written incorrectly(?)

8 0
2 years ago
In 2010, the Census Bureau estimated the proportion of all Americans who own their homes to be 0.669. An urban economist wants t
Alexxandr [17]

Answer:

i)

Sample size making use of the Census Bureau: 1,499 American adults.

Sample size without making use of the Census Bureau: 1,692 American adults

ii)

71

Step-by-step explanation:

i)

The sample size n in Simple Random Sampling is given by

\bf n=\frac{z^2p(1-p)}{e^2}

where  

<em>z = 1.645 is the critical value for a 90% confidence level </em><em>(*) </em>

<em>p= 0.669 is the population proportion given by the Census  </em>

<em>e = 0.02 is the margin of error </em>

so  

\bf n=\frac{(1.645)^2*0.669*0.331}{0.02^2}=1,498.05\approx 1,499

rounded up to the nearest integer.

(*)This is a point z such that the area under the Normal curve N(0,1) 1nside the interval [-z, z] equals 90% = 0.9

<em>It can be obtained with tables or in Excel or OpenOffice Calc with </em>

<em>NORMSINV(0.95) </em>

<em> </em>

If she ignores the Census estimate, the she has to take the largest sample possible that meets the requirements.

Let's show it is obtained when p = 0.5

As we said, the sample size n is

\bf n=\frac{z^2p(1-p)}{e^2}

where  

e = 0.02 is the error proportion  

z = 1.645

hence

\bf n=\frac{(1.645)^2p(1-p)}{(0.02)^2}=6765.0625p(1-p)=6765.0625p-6765.0625p^2

taking the <em>derivative</em> with respect to p, we get

n'(p)=6765.0625-2*6765.0625p

and  

n'(p) = 0 when p=0.5

By taking the second derivative we see n''(p)<0, so p=0.5 is a maximum of n

<em>This means that if we set p=0.5, we get the maximum sample size for the confidence level required for the proportion error 0.02 </em>

Replacing p with 0.5 in the formula for the sample size we get

\bf n=6765.0625*0.5-6765.0625(0.5)^2=1691.27\approx 1,692

rounded to the nearest integer.

ii)

When we do not have a proportion but a variable whose approximate standard deviation s is known, then the sample size n in Simple Random Sampling is given by

\bf n=\frac{z^2s^2}{e^2}

where  

<em>z = 2.241 is the critical value for a 95% confidence level </em><em>(*) </em>

<em>s = 7.5 is the estimated population standard deviation </em>

<em>e = 2 hours is the margin of error </em>

so  

\bf n=\frac{z^2s^2}{e^2}=\frac{(2.241)^2(7.5)^2}{(2)^2}=70.62\approx 71

(*)This is a point z such that the area under the Normal curve N(0,1) inside the interval [-z, z] equals 95% = 0.95

<em>It</em> <em>can be obtained in Excel or OpenOffice Calc with </em>

<em>NORMSINV(0.9875) </em>

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4 years ago
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Svet_ta [14]
18 because 6=22. 12=44. 18=66
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3 years ago
Due:gebra 1: Problem of the Week1) Dylan invested $600 in a savings account at a 1.6% annual interest rate. He made nodeposits o
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19.20 cents i believe 
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4 years ago
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