Inverse variation is of the form y=k/x (direct variation is of the form y=kx)
We are given that x=2 when y=1 so using the inverse form y=k/x we can solve for the constant of variation...
1=k/2
k=2
so the equation is:
y=2/x now they want us to find y when x=-1 so
y=2/-1
y=-2
Answer:
<h2>4</h2>
Step-by-step explanation:

Answer:
Width = 4 m
Length = 7 m
Step-by-step explanation:
given:
perimeter of a rectangle = 22m
L = 3 + W
perimeter = 2L + 2W
perimeter = 2 (3 + W) + 2W
22 = 6 + 2W + 2W
22 - 6 = 4W
W = 16 / 4
W = 4 m
L = 3 + W
L = 3 + 4
L = 7 m
check:
perimeter = 2L + 2W
22 = 2(7) + 2(4)
22 = 14 + 8
22 = 22 ---- OK
Answer:
The fifth degree Taylor polynomial of g(x) is increasing around x=-1
Step-by-step explanation:
Yes, you can do the derivative of the fifth degree Taylor polynomial, but notice that its derivative evaluated at x =-1 will give zero for all its terms except for the one of first order, so the calculation becomes simple:

and when you do its derivative:
1) the constant term renders zero,
2) the following term (term of order 1, the linear term) renders:
since the derivative of (x+1) is one,
3) all other terms will keep at least one factor (x+1) in their derivative, and this evaluated at x = -1 will render zero
Therefore, the only term that would give you something different from zero once evaluated at x = -1 is the derivative of that linear term. and that only non-zero term is:
as per the information given. Therefore, the function has derivative larger than zero, then it is increasing in the vicinity of x = -1