Answer:
It will take the boulder approximately 4.28 seconds to hit the road
Step-by-step explanation:
The given height of the cliff from which the boulder falls, h = 90 feet
The equation that can be used to find the time it takes the boulder to fall is h = u·t + (1/2)·g·t²
Where;
h = The height of the cliff = 90 ft.
u = The initial velocity of the boulder = 0 m/s (The boulder is assumed to be at rest when it falls)
g - The acceleration due to gravity ≈ 9.81 m/s²
t = How long it will take for the boulder to hit the road below
Plugging in the values gives;
90 = 0 × t + (1/2)×9.81×t² = 4.905·t²
∴ t = √(90/4.905) ≈ 4.28
The time it takes the boulder to hit the road, t ≈ 4.28 seconds.
Answer:
oofu will expect hell you will really need to tudy sooo much like how i study
Step-by-step explanation:
We are asked to find unknown or the missing number to complete the polynomial given in the problem which is x² + ?x -49. First, let us equate the number to be equal to zero such as it would become x² + ?x - 49 = 0. Next, we need to find the factors such that it would produce a difference of squares and these two factors are a = +7 and b = -7. Hence, the complete solution is shown below:
(x + 7) (x-7) = 0
perform distribution and multiplication of terms such as shown below:
x² + 7x - 7x - 49 = 0
Combine the same term such as we can either add or subtract +7x to -7x and the result will be equal to 0x.
x² + 0x - 49 = 0
Therefore, the missing number is 0. The answer is 0 which will result to x² +0x - 49.
Answer:
$55.13
Step-by-step explanation:
50 * 1.05 = 52.5
<em>We do this step twice because the interest is for </em><em>2 years.</em>
52.5 * 1.05 = 55.125
<em>This rounds up to 55.13, your final answer!</em>
Use a proportion.
A ratio of 44 blue to 33 yellow is the same as a ratio of 4 blue to 3 yellow.
Since you are told the total of cards, 84, add 3 + 4 = 7
In the deck, the cards are int he ratio of 4 blue to 3 yellow to 7 total.
4 blue to 7 total = x blue to 84 total
4/7 = x/84
7x = 4 * 84
x = 4 * 12
x = 48
There are 48 blue cards.
