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I am Lyosha [343]
3 years ago
14

Juanita did this work to solve an equation. Did she make an error?

Mathematics
1 answer:
yulyashka [42]3 years ago
7 0

Answer

Step-by-step explanation:

if you added more detail to the question i could have helped you!!

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Find the result of 765 times 95 divided by 5?<br><br>please help me ​
Marizza181 [45]

Answer:

14,535

Step-by-step explanation:

765 times 95 : 765 x 95 = 72,675

divided by 5 : \frac{ 72,675}{5} = 14,535

Let me know if you want an even more in-depth answer

Happy to do so !

7 0
2 years ago
The drama club spent $336 on T-shirts if each t-shirt cost $12 how many t-shirts did the drama club buy? what strategy would be
mr_godi [17]

Answer:

28 t-shirts

Step-by-step explanation:

x = # of t-shirts

12x = 336

x = 28

3 0
3 years ago
The histogram shows the number of yards gained on first downs. How many times did the team gain at least 6 yards on first downs?
BabaBlast [244]

Answer:

8 times

Step-by-step explanation:

Given

The attached histogram

Required

The number of times the team gain at least 6 yards

From the question, the entry that fall in the category of at least 6 yards are:

6\ to\ 8, 9\ to\ 11 and 12\ to\ 14

Their frequencies are:

5, 2 and 1 respectively

So, the number of times is:

Times = 5 + 2 + 1

Times =8

4 0
3 years ago
Read 2 more answers
In the game of​ roulette, a player can place a ​$8 bet on the number 17 and have a StartFraction 1 Over 38 EndFraction probabili
svp [43]

Answer:

Expected value of the game: -$0.421

Expected loss in 1000 games: $421

Step-by-step explanation:

There are two possible outcomes for the event:

- There is a 1 in 38 chance of winning $280

- There is a 37 in 38 chance of losing $8

The expected value for a single game is:

E(X) = \frac{1}{38}*\$280-\frac{37}{38}*\$8\\E(X)=-\$0.421

The expected value of the game is -$0.421

In 1,000 plays, the expected loss is:

L = 1,000*-\$0.421\\L=-\$421

You would expect to lose $421.

3 0
3 years ago
The water level in a lake was 22 inches below normal at the beginning of March. The water level decreased by 3 1/6 inches in Mar
Vinvika [58]
At the beginning it was 22 inches below normal (-22).
Then it decreased by 3 1/6 (-19/6).
Then increased by 1 6/7 (+13/7)

-22 - 19/6 + 13/7
-924/42 - 133/42 + 78/42
-1057/42 + 78/42
-979/42
-23 13/42

It was 23 13/42 inches below normal after April.
8 0
3 years ago
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