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3 years ago

8

The bus from Karen's house to school runs 26 to 75 minutes of the bus runs on Monday at 7:05am at which time could the bus run n

ext

1 answer:

Citrus2011 [14]3 years ago

8 0

I’m pretty sure the answer is 8:25 a.m

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I the cafeteria there are 7 teachers 48 girls and 45 boys. What is the probability that a person chosen at random from the cafet

mr Goodwill [35]

Total people in the cafeteria = 7 + 48 + 45 = 100

There are 45 boys.

The probability would be the number of boys over the total number of people:

45/100, which simplifies to 9/20

7 0

2 years ago

Read 2 more answers

Add and simplify

Tanya [424]

Answer:

Your 1st answer is correct

Step-by-step explanation:

$\frac{1}{(x - 1)} - \frac{3}{(1 - x)} + 2$

$\frac{1}{(x - 1)} - \frac{3}{ - (x - 1)} + 2$

$\frac{1}{(x - 1)} + \frac{3}{(x - 1)} + 2$

$\frac{4}{(x - 1)} + 2$

$\frac{4 + 2(x - 1)}{x - 1}$

$\frac{4 + 2x - 2}{x - 1}$

$= \frac{2x + 2}{x - 1}$

$= \frac{2(x + 1)}{x - 1}$

6 0

2 years ago

Chase buys a bag of cookies that contains 6 chocolate chip cookies, 6 peanut butter cookies, 6 sugar cookies and 6 oatmeal cooki

Over [174]

Answer:

0.0652173

Step-by-step explanation:

Given that :

6 chocolate chip cookies

6 peanut butter cookies

6 sugar cookies

6 oatmeal cookies

Total number of cookies purchased = (6+6+6+6) = 24

Probability, P= required outcome /total possible outcomes

This is a selection without replacement probability problem :

P(peanut butter cookies) = 6/24 = 1/4

Then ;

P(chocolate chip cookie) = 6/23

Hence,

P(peanut butter cookies then chocolate chip cookie) = 1/4 * 6/23 = 0.0652173

4 0

2 years ago

the first group of students consists of 10 and their average age was 13 years old the next group consisted of 30 students and th

Kazeer [188]

Answer: The average was 9 years old find the average age of both groups is 10 years old.

Step-by-step explanation:

Formula foe average : $\text{Average} =\dfrac{\text{Sum of all observations}}{\text{Number of observations}}$

Given : The first group of students consists of 10 and their average age was 13 years old.

i.e. $13=\dfrac{\text{Sum of ages of students of first group}}{10}\\\\\Rightarrow\ \text{Sum of ages of students of first group}=13\times10=130$ (1)

The next group consisted of 30 students and their average was 9 years old.

i.e. $9=\dfrac{\text{Sum of ages of students of next group}}{30}\\\\\Rightarrow\ \text{Sum of ages of students of nextgroup}=9\times30=270$ (2)

Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400

Combined students of both groups (first and next group )= 10+30=40

Now , the average of both groups = $\dfrac{\text{Sum of combined students}}{\text{combined students}}$

$=\dfrac{400}{40}=10$

Hence, the average was 9 years old find the average age of both groups is 10 years old.

4 0

3 years ago

3/4x < 33<br> Solve the inequality

slava [35]

answer:

x < 44

step-by-step explanation:

solve this like an equation

<u>3/4x < 33</u>

in order to solve this we can multiply this with the denominator first to cross out the fraction and be left with a whole number

3/4x < 33

3/4x(4) < 33(4)

3x < 132

x < 44

4 0

2 years ago