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3 years ago

Is 9,13,16 a right triangle

Mathematics

1 answer:

Dvinal [7]3 years ago

5 0

We can check by using the

pythagorean theorem or a² + b² = c².

Substitute your values in for a, b, and c.

(9)² + (13)² = (16)²

~simplify

81 + 169 ≠ 256

81 + 169 is 250 but 16² is 256.

So, this in not a right triangle.

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Solve the following equation by factoring:9x^2-3x-2=0

olya-2409 [2.1K]

Answer:

The two roots of the quadratic equation are

$x_1= - \frac{1}{3} \text{ and } x_2= \frac{2}{3}$

Step-by-step explanation:

Original quadratic equation is $9x^{2}-3x-2=0$

Divide both sides by 9:

$x^{2} - \frac{x}{3} - \frac{2}{9}=0$

Add $\frac{2}{9}$ to both sides to get rid of the constant on the LHS

$x^{2} - \frac{x}{3} - \frac{2}{9}+\frac{2}{9}=\frac{2}{9}$ ==> $x^{2} - \frac{x}{3}=\frac{2}{9}$

Add $\frac{1}{36}$ to both sides

$x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{2}{9} +\frac{1}{36}$

This simplifies to

$x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{1}{4}$

Noting that (a + b)² = a² + 2ab + b²

If we set a = x and b = $\frac{1}{6}\right)$ we can see that

$\left(x - \frac{1}{6}\right)^2$ = $x^2 - 2.x. (-\frac{1}{6}) + \frac{1}{36} = x^{2} - \frac{x}{3}+\frac{1}{36}$

$\left(x - \frac{1}{6}\right)^2=\frac{1}{4}$

Taking square roots on both sides

$\left(x - \frac{1}{6}\right)^2= \pm\frac{1}{4}$

So the two roots or solutions of the equation are

$x - \frac{1}{6}=-\sqrt{\frac{1}{4}}$ and $x - \frac{1}{6}=\sqrt{\frac{1}{4}}$

$\sqrt{\frac{1}{4}} = \frac{1}{2}$

So the two roots are

$x_1=\frac{1}{6} - \frac{1}{2} = -\frac{1}{3}$

and

$x_2=\frac{1}{6} + \frac{1}{2} = \frac{2}{3}$

7 0

2 years ago

What percent of 90 is 36

levacccp [35]

The percentage of 90 is 36 is 250%

4 0

3 years ago

-16+5n=-7(-6+8n)+3 what is the work for this ?? this is the like only one i cant get

uranmaximum [27]

-16 + 5n = -7(-6 + 8n) + 3 Given
-16 + 5n = 42 - 56n + 3 Distribute
-16 + 5n = 45 - 56n Collect like terms
61n = 61 Add 56n to the left side and add 16 to the right side
n = 1 Divide 61 from both sides

The answer is n = 1. Remember that when you have a number beside two or more numbers in parentheses, you have to distribute, or multiply the number outside the parentheses by each number inside the parentheses.

Hope this helps!

4 0

4 years ago

Tell whether x=6 is a solution of x−1 ≤ 7.

MrRa [10]

Answer:

x = 6 is a solution of x - 1 $\leq$ 7.