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Brrunno [24]
3 years ago
14

I NEED HELP AND IM ON A TIMED TEST

Mathematics
1 answer:
stira [4]3 years ago
7 0

This Question is not Complete

Complete question

The number of absences per student in each of two classes is shown on the dot plots below.

A dot plot titled Number of absences per student in Misses Anderson's class. The number line goes from 0 to 6. There is 1 dot above 0, 3 above 1, 3 above 2, 3 above 3, 1 above 4, and 0 above 5 and 6.

A dot plot titled Number of absences per student in Misses Bergot's class. The number line goes from 0 to 6. There is 1 dot above 0, 1 above 1, 2 above 2, 3 above 3, 2 above 4, 1 above 5, and 1 above 6.

Which statements accurately compare the two data sets? Select three options.

a. The mean number of absences is greater in Mrs. Anderson’s class.

b. The mean number of absences is greater in Mrs. Bergot’s class.

c. There is more variability in Mrs. Anderson’s data set.

d. There is more variability in Mrs. Bergot’s data set.

e. The mean and MAD are better representations of these data sets than the median and IQR.

Answer:

b. The mean number of absences is greater in Mrs. Bergot’s class.

d. There is more variability in Mrs. Bergot’s data set.

e. The mean and MAD are better representations of these data sets than the median and IQR.

Step-by-step explanation:

From the above data given in the question and the options given to us, we can observe from the comparison of both the number of absences in Mrs Bergot's class to that in Mrs Anderson's class, there will be a presence of variation in the data of one of the classes and that class happens to be Mrs Bergot's class.

The appropriate statistical tool that we can be used to determine and measure the centre of variability of the data is Mean and Mean Absolute Deviation.

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he numbers of regular season wins for 10 football teams in a given season are given below. Determine the​ range, mean,​ variance
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Answer:

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Step-by-step explanation:

2​, 10​, 15​, 3​, 13​, 9​, 14​, 7​, 2​, 9

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Let the set of data be arranged inn ascending order

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For variance

Variance=((2-8.4)²+(2-8.4)²+(3-8.4)²+(7-8.4)²+(9-8.4)²+(9-8.4)²+(10-8.4)²+(13-8.4)²+(14-8.4)²+(15-8.4)²)/10

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2 years ago
A rectangular parking lot has a perimeter of 820 ft. The area of the parking lot measure SL 42,000 ft
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Answer:

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Step-by-step explanation:

My assumption is, we have to find the length of sides of rectangle

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area = a*b = 42,000 ft^2 (ii)

from eq (1)

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