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defon
2 years ago
12

Which of the following is the product of the rational expression shown below? 5/2x-1 x 6/x

Mathematics
2 answers:
kirill115 [55]2 years ago
7 0

It’s 30/2x^2+x (apex)

Rina8888 [55]2 years ago
4 0

Answer:

30/(2x^2-x)

Step-by-step explanation:

5/(2x-1) * 6/x

Multiply the numerators

5*6 = 30

Multiply the denominatos

(2x-1) *x = 2x^2 -x


5/(2x-1) * 6/x = 30/x(2x-1) = 30/(2x^2-x)

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Answer:

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Step-by-step explanation:

they are all equal sides so what you'd do is 28+28+28= 84

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Answer:

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Step-by-step explanation:

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If tanA=a <br>then find sin4A-2sin2A/ sin4A+2sin2A​
anygoal [31]

Answer:

The value of the given expression is

\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2

Step by step Explanation:

Given that tanA=a

To find the value of \frac{sin4A-2sin2A}{sin4A+2sin2A}

Let us find the value of the expression :

\frac{sin4A-2sin2A}{sin4A+2sin2A}=\frac{2cos2Asin2A-2sin2A}{2cos2Asin2A+2sin2A} ( by using the formula sin2A=2cosAsinA here A=2A)  

=\frac{2sin2A(cos2A-1)}{2sin2A(cos2A+1)}

=\frac{(cos2A-1)}{(cos2A+1)}

=\frac{(-(1-cos2A))}{(1+cos2A)}(using  sin^2A+cos^2A=1  here A=2A)

=\frac{-(sin^2A+cos^2A-(cos^2A-sin^2A))}{sin^2A+cos^2A+(cos^2A-sin^2A)}(using cos2A=cos^2A-sin^2A here A=2A)

=\frac{-(sin^2A+cos^2A-cos^2A+sin^2A)}{sin^2A+cos^2A+(cos^2A-sin^2A)}

=\frac{-(sin^2A+sin^2A)}{cos^2A+cos^2A}

=\frac{-2sin^2A}{2cos^2A}

=-\frac{sin^2A}{cos^2A}

=-tan^2A  ( using tanA=\frac{sinA}{cosA} here A=2A )

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Therefore \frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2

6 0
3 years ago
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timurjin [86]

Answer:

In math, value can either refer to the result of a calculation or a variable or constant

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Anastaziya [24]

Answer:

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