Answer:
Because of the range of the sine function.
Step-by-step explanation:
The reason why the value of the sine ratio for an acute angle
of a right triangle must always be a positive value less
than 1 has to do with the the range of the sine function.
The range of the sine function is
But in the first quadrant all y-values are positive and acute angles are less than 90°.
Therefore the range will now be 0≤y<1 for acute angles.
We see that in these 3 terms, 6 is a common factor. So, let's factor out a 6:
We can set this equal to 0 and factor by using the quadratic formula which is:
So, let's do just that:
Note that the 6 goes away if you divide both sides by 6. In this case, a = 1, b = -1, and c = -2. Let's plug that into the quadratic equation:
So, we can write this as:
Notice that the 6 comes back because it was only temporarily mad. And that the roots have opposite signs in the parentheses because to find the roots, you need to set each parentheses equal to 0 and solve for n. With that in mind, your final answer is 6(n-1)(n+2). Hope I could help you!
