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3 years ago

A quantity h varies directly with w and inversely with p. If h = 2, w = 4, and p = 6. What is the constant of variation?

Mathematics

2 answers:

Shalnov [3]3 years ago

7 0

Answer with Step-by-step explanation:

A quantity h varies directly with w and inversely with p.

i.e. h ∝ w/p

Let k be the constant of variation

then, h = kw/p

h = 2, w = 4, and p = 6

We have to find the value of k

2 = 4k/6

Multiplying both sides by 6, we get

12 = 4k

dividing both sides by 4, we get

k = 3

Hence, Constant of variation is:

GREYUIT [131]3 years ago

5 0

H α w/p

h = kw/p where k = constant of variation.

h*p = kw

hp/w = k

k = hp/w

k = 2*6/4

k = 3

Constant of variation = 3.

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3 years ago

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3 years ago

The owner of a local golf course wants to estimate the difference between the scores of golfers on his golf course and the score

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Answer:

(8) The correct option is (3).

(2) The correct option is (1).

Step-by-step explanation:

(8)

The hypothesis can be defined as:

H₀: There is no difference between the two population means, i.e. μ₁ = μ₂.

Hₐ: There is a difference between the two population means, i.e. μ₁ ≠ μ₂.

The decision rule of the test based on confidence interval is:

If the (1 - α) % confidence interval consists the null hypothesis value then the null hypothesis is not rejected. and vice-versa.

The 90% confidence interval for the paired difference between means is, (-3.31, 14.74).

The interval consists the null value, 0.

Thus, the null hypothesis was failed to be rejected.

Conclusion:

No significant difference exists between the average difference in scores and the differences were calculated as 0.

Thus, the correct option is (3).

(2)

A (1 - α) % confidence interval implies that there is (1 - α) % chance of the population parameter to be contained in this interval.

Or if 100 such intervals are constructed then (1 - α) of these intervals will consist the true parameter value.

The 99% confidence interval for the difference between means is, (-0.124, 13.85).

This interval implies that the true mean difference between the two populations lies in this interval with probability 0.99.

Conclusion:

We are 99% confident that the difference between the average age of all men and all women who play golf at the course is between -0.124 and 13.85.

Thus, the correct option is (1).

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3 years ago