First, multiply both sides by m:
s*m = w - 10e
Then add 10e to both sides to isolate w:
s*m + 10e = w
or
w = s*m + 10e
<span>Group A (distance in miles) 1 1.5 3.03 3.2 2.8 1.5 1.8 2.5 2.2
Group B (distance in miles) 2 2.5 3.23 1.3 1.8 2.4 3 1.5 1.8
Group A mean = (1 + 1.5 + 3.03 + 3.2 + 2.8 + 1.5 + 1.8 + 2.5 + 2.2)/9 = 19.53/9 = 2.17
Group B mean = (2 + 2.5 + 3.23 + 1.3 + 1.8 + 2.4 + 3 + 1.5 + 1.8)/9 = 19.53/9 = 2.17
Therefore, the mean is equal for Group A and Group B.
</span>
Answer:
1/2 5/8 11/16
Step-by-step explanation:
i hope this is right for you good luck
1<em>.) </em><em>Reduction</em>
<em>As you can see Triangle A was reduced in size as a result of Triangle B</em>
<em>2.) </em><em>Enlargement</em>
<em>Square A is much smaller than square B, making this an enlargement</em>
<em>3.) </em><em>Enlargement</em>
<em>The quadrilateral shown here gets larger with quadrilateral B</em>
<em>4.) </em><em>Reduction</em>
<em>This object gets vividly smaller as shown on the graph, making it a reduction </em>
By using distance formula :

Given points = ( 3 , 5.25 ) and ( 3 , - 8.75 )

On applying formula, we get

Hence, Option D is correct.