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Advocard [28]
3 years ago
12

(-5)+(-2)= porfa xdlo necesito rapido plox

Mathematics
2 answers:
Lina20 [59]3 years ago
7 0

Answer:

-7

Step-by-step explanation:

Karolina [17]3 years ago
4 0

Answer:

-7

Step-by-step explanation:

You use your common sense

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7x + 3y + 2x<br><br> Please help me
Pachacha [2.7K]

Answer:

Your expression would be 9x + 3y

Step-by-step explanation:

Coefficients with the same variables can be added together

7 0
3 years ago
Read 2 more answers
The fifth grade teachers took their classes on a field trip to museum first group had 25 students and two teachers and cost $97.
iren [92.7K]

Answer:


Step-by-step explanation:

S=student cost; T=teacher cost

.

32S+3T=$127 . Multiply this by 2.

64S+6T=$254 Subtract this below

.

25S+2T=$97.50 . Multiply this by 3.

75S+6T=$292.50

64S+6T=$254 . Subtract this (from above.)

.

11S=$38.50

S=$3.50

ANSWER 1: Student tickets cost $3.50.


.

32S+3T=$127

32($3.50)+3T=$127

$112+3T=$127

3T=$15

T=$5.00

ANSWER 2: Teacher tickets cost $5.00.

.

CHECK:

25S+2T=$97.50

25($3.50)+2($5.00)=$97.50

$87.50+$10.00=$97.50

$97.50=$97.50


4 0
3 years ago
Evaluate 64 divided by [4 x (27 - 10)]
KatRina [158]
Using PEMDAS,
27-10=17
17*4=68
64/68=0.94 (rounded to the nearest hundredth) 
8 0
3 years ago
Read 2 more answers
What is the mean for the following 5, 7, 8, 10, 12, 12
miss Akunina [59]

Answer:

44

Step-by-step explanation:

the answer is 44 because 44 is the average and your wondering how i got 44 you add all the numbers up which will be 54 and divide by all the total numbers you have so in that case you hvae 6 numbers so 54 divide by 6 is 44

6 0
3 years ago
Read 2 more answers
How to solve logarithmic equations as such
Serga [27]

\bf \textit{exponential form of a logarithm} \\\\ \log_a b=y \implies a^y= b\qquad\qquad a^y= b\implies \log_a b=y \\\\\\ \begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} ~\hspace{7em} \begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \log_2(x-1)=\log_8(x^3-2x^2-2x+5) \\\\\\ \log_2(x-1)=\log_{2^3}(x^3-2x^2-2x+5) \\\\\\ \log_{2^3}(x^3-2x^2-2x+5)=\log_2(x-1) \\\\\\ \stackrel{\textit{writing this in exponential notation}}{(2^3)^{\log_2(x-1)}=x^3-2x^2-2x+5}\implies (2)^{3\log_2(x-1)}=x^3-2x^2-2x+5

\bf (2)^{\log_2[(x-1)^3]}=x^3-2x^2-2x+5\implies \stackrel{\textit{using the cancellation rule}}{(x-1)^3=x^3-2x^2-2x+5} \\\\\\ \stackrel{\textit{expanding the left-side}}{x^3-3x^2+3x-1}=x^3-2x^2-2x+5\implies 0=x^2-5x+6 \\\\\\ 0=(x-3)(x-2)\implies x= \begin{cases} 3\\ 2 \end{cases}

5 0
3 years ago
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