Step-by-step explanation:
the distance of a vertex on the 2 outgoing sides to the touching points with the inscribed circle is the same for both sides.
and that applies to all 3 vertexes.
so, we know for the top left vertex the distance to both touching points is 4.
that means the distance to the touching points from the bottom left vertex is 7-4 = 3.
and that means that the distance to the touching points from the bottom right vertex is 16-3 = 13.
so, x = 13
it is the distance to one of the touching points for the bottom right vertex.
and the perimeter of the triangle is therefore
7 + 16 + (13 + 4) = 40
Is there any numbers to answer the question?
If that is 6-3(log2n)=0 then how you would go about solving it is by looking at log2n like x. In this case, for 6-3x=0, x would have to =2. So log2n has to =2. If log2n=2 and we assume that the base is 10 (because if there is no written base on a log then it is 10) then we need to rewrite the log to exponential form. Rewritten it's 10^2=2n. 100=2n, divide both sides by 2 and you get n=50.
Answer:
Step-by-step explanation:e equation has a leading coefficient of 1 or if the equation is a difference of squares. The zero-factor property is then used to find solutions. ... Another method for solving quadratics is the square root property. The variable is squared.