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exis [7]
4 years ago
11

Rectangle ABCD has vertices A(4, 8), B(8, 8) , C(8, −4) and D(4, −4) . The rectangle is dilated by a scale factor of 3/4 , with

the origin as the center of dilation. What are the coordinates of the vertices in the image? Enter your answers in the boxes.
Mathematics
1 answer:
Vinil7 [7]4 years ago
4 0

Answer:

A'(3, 6)

B'(6, 6)

C'(6, -3)

D'(3, -3)

Step-by-step explanation:

To find the image of a geometric figure after a dilation centered at the origin, you just need to multiply each vertex of the geometric figure by the scale factor.

We know that the scale factor is \frac{3}{4}, so let's multiply each vertex by it:

A=(4, 8), so

A'=\frac{3}{4} (4,8)=(\frac{3}{4} *4,\frac{3}{4} *8)=(3,6)

B=(8,8)

B'=(\frac{3}{4} *8,\frac{3}{4} *8)=(6,6)

C=(8,-4)

C'=(\frac{3}{4} *8,\frac{3}{4} *-4)=(6, -3)

D=(4,-4)

D'=(\frac{3}{4} *4,\frac{3}{4} *-4)=(3,-3)

We can conclude that the vertices of the image are A'(3, 6), B'(6, 6), C'(6, -3), and D'(3, -3)

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