Problem 1
<h3>Answer: False</h3>
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Explanation:
The notation (f o g)(x) means f( g(x) ). Here g(x) is the inner function.
So,
f(x) = x+1
f( g(x) ) = g(x) + 1 .... replace every x with g(x)
f( g(x) ) = 6x+1 ... plug in g(x) = 6x
(f o g)(x) = 6x+1
Now let's flip things around
g(x) = 6x
g( f(x) ) = 6*( f(x) ) .... replace every x with f(x)
g( f(x) ) = 6(x+1) .... plug in f(x) = x+1
g( f(x) ) = 6x+6
(g o f)(x) = 6x+6
This shows that (f o g)(x) = (g o f)(x) is a false equation for the given f(x) and g(x) functions.
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Problem 2
<h3>Answer: True</h3>
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Explanation:
Let's say that g(x) produced a number that wasn't in the domain of f(x). This would mean that f( g(x) ) would be undefined.
For example, let
f(x) = 1/(x+2)
g(x) = -2
The g(x) function will always produce the output -2 regardless of what the input x is. Feeding that -2 output into f(x) leads to 1/(x+2) = 1/(-2+2) = 1/0 which is undefined.
So it's important that the outputs of g(x) line up with the domain of f(x). Outputs of g(x) must be valid inputs of f(x).
A shape that is similar to another shape will be enlarged by a scale factor.
Each corresponding sides should give the same scale factor
Side GI corresponds to side JL
Side GH corresponds to side JK
Side HI corresponds to side KL
The correspond sides whose length are given is
GH = 4 and JK = 8
Side JK is twice longer than GH
All the other sides of triangle JKL are twice longer than triangle GHI, so we want that the side JL to be twice of the sides GI
Side GI = 6
Side JL = 6 × 2 = 12
Answer: y = 12
Answer:
(1)3(x+3)
(2)5(x+3)
Step-by-step explanation:
(1) common taking
(2) common taking
Answer:
The length of each red rod is 10 cm and the length of each blue rod is 14 cm
Step-by-step explanation:
Let
x ----> the length of each red rod in centimeters
y ----> the length of each blue rod in centimeters
we know that
----> equation A
----> equation B
Solve the system by graphing
Remember that the solution of the system of equations is the intersection point both graphs
using a graphing tool
The solution is the point (10,14)
see the attached figure
therefore
The length of each red rod is 10 cm and the length of each blue rod is 14 cm