If an event occurs 0 times (out of 4, in this case) then it does not occur at least once. So we can find the probability of it not occurring and then subtract that value from 1.
So, what are the chances of it not occurring in 1 trip?
1−.37=.63
What about not occurring in 2 trips?
(1−.37)⋅(1−.37)=.63⋅.63=.3969
Now what about not occurring in 4 trips?
.63^4 = 0.15752961
We must subtract this value from 1
(recall that what we just calculated is the probability of it not occurring, so the probability of it occurring at least once is:
1−0.15752961 = .84247039
TLDR - In 4 trips the chance of a guest catching a cutthroat once in under 4 trips in 0.84.
Answer: Sunday by 2 miles
Step-by-step explanation:
Answer:
make 360×each number given/15 students to start drawing
360×7/15=168°
360×5/15=120°
360×2/15=48°
360×1/15=24°
now draw each one from the radius give to the clockwise
if you don't know what's clockwise direction, see it from your house or tell anybody in your home to tell you where is clockwise
after you finish drawing, label each section by writing the names on the correct sections ( you can write in or out of the circle)
Answer: yes
Step-by-step explanation: