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Gnom [1K]
3 years ago
9

Help pls if its linear or nonlinear

Mathematics
2 answers:
jek_recluse [69]3 years ago
8 0

Answer:

linear prob

Step-by-step explanation:

I think it is don't quote me on that

pshichka [43]3 years ago
4 0

Answer:

linear

Step-by-step explanation:

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The table shows the distance traveled over time while traveling at a constant speed.
Setler79 [48]

Answer:1,200 meters per minute

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A plane travels a distance of 22,000km in a time of 3.6 hours. What is its average speed rounded to the nearest whole number
fredd [130]

Answer:6111 km/hr

Step-by-step explanation:

Given

Distance travels by plane d=22,000 km

time taken t=3.6 hours

\text{distance}=\text{speed}\times\text{time}

average speed

v_{avg}=\dfrac{22,000}{3.6}=6111.11\approx 6111\ km/hr

4 0
3 years ago
Gaurav takes 15 rounds of a rectangular park whose length is twice its breadth. If the total distance covered by Gaurav is 900m
Dvinal [7]

Answer:

length = 20 breadth = 10

Step-by-step explanation:

divide 900 by 15

= 60

60 divided by 6 because the length is twice the breath

60 / 6 is 10

so ten is the breadth of one side and double that is 20 so the length is 20

Hope this helped!

4 0
3 years ago
A random sample of 9 wheels of cheese yielded the following weights in pounds has a sample mean of 20.90 and a sample variance o
Ronch [10]

Answer:

2.002 \leq \sigma^2 \leq 11.365

Step-by-step explanation:

1) Data given and notation

s represent the sample standard deviation

s^2 represent the sample variance

n=9 the sample size

Confidence=90% or 0.90

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

On this case we need to find the sample standard deviation with the following formula:

s=sqrt{\frac{\sum_{i=1}^9 (x_i -\bar x)^2}{n-1}}
The sample variance given was [tex]s^2=3.45

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=9-1=8

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.05,8)" "=CHISQ.INV(0.95,8)". so for this case the critical values are:

\chi^2_{\alpha/2}=15.507

\chi^2_{1- \alpha/2}=2.732

And replacing into the formula for the interval we got:

\frac{(9)(3.45)}{15.507} \leq \sigma \frac{(9)(3.45)}{2.732}

2.002 \leq \sigma^2 \leq 11.365

7 0
3 years ago
How do I do this on a
sergiy2304 [10]
On a what? graph? line? 
7 0
3 years ago
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