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SashulF [63]
1 year ago
7

Is centroid and Circumcentre same?

Mathematics
1 answer:
makvit [3.9K]1 year ago
7 0

No, the centroid and Circumcentre are not same but it is same in equilateral triangle.

The intersection of a triangle's perpendicular bisectors is called the circumcenter.A triangle's circumcenter is a location that is equally spaced from each of its vertices.The centroid of a triangle is the location where its medians connect.

Triangle's centroid is always within it. The centroid of a triangle is its center of gravity in physical terms. If the triangle is evenly distributed around the plane's surface and you want to balance it by supporting it at only one point, you must do it near the center of gravity.Are the circumcenter and centroid at the same location? In the case of an equilateral triangle, they will both be.

Therefore, the centroid and Circumcentre are not same but it is same in equilateral triangle.

To learn more about circumcenter click here:

brainly.com/question/16276899

#SPJ4

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What is the next term of the geometric sequence? 4/9, -4/3, 4
andreev551 [17]

Answer:

-12

Step-by-step explanation:

To find the ration, take the second term and divide by the first term

-4/3 ÷ 4/9

Copy dot flip

-4/3 * 9/4

-3

Multiply each term by -3

4*-3 =-12

5 0
3 years ago
Listen Rachel babysat three children for five hours if they were paid $2.50 per hour for each child and divided their earnings e
lina2011 [118]

Answer: Each girl will receive $18.75.

Step-by-step explanation:

Given: Two girls babysat three children for five hours.

Hourly pay for each child = $2.50

Payment for 5 hours per child = 5\times\$2.50=\$12.5

Payment to 3 children for 5 hours = 3\times \$12.5=\$37.5

So, the amount received by each girl  = \dfrac{\text{Payment to 3 children for 5 hours}}{2}

=\dfrac{37.5}{2}=\$18.75

Hence, each girl will receive $18.75.

5 0
3 years ago
Equation for the line perpendicular to the line -6x-7y=-6 having the same y-intercept as 8x-5y=10
PilotLPTM [1.2K]
Solving   <span>8x-5y=10   for y helps us to identify the y-intercept:

-5y = -8x + 10.  Dividing both sides by -5, we get (8/5)x -2.  Therefore, y = (8/5)x - 2; the y-intercept is (0,-2).

The equation  </span><span>-6x-7y=-6   can be solved for its slope in the same manner.
7y = -6x + 6;  then y = (-6/7)x + 6/7.  Its slope is -7/6.  A line perpendicular to this line has slope equal to the negative reciprocal of -7/6,  which is 6/7.

So, using the slope-intercept form, y = mx + b becomes y = (6/7)x -2.</span>
4 0
3 years ago
Find the length of side x in simplest radical form with a rational denominator
Yakvenalex [24]

Answer:

x = √(10)/2

Step-by-step explanation:

Here, we want to get the measure of the side marked x

what we have is an isosceles right triangle since the two acute angles of the right triangle are 45 degrees each

Hence, the other last side will measure x too

Mathematically, according to Pythagoras’; the square of the hypotenuse equals the sum of the squares of the two other sides

Thus;

x^2 + x^2 = (√5)^2

2x^2 = 5

x^2 = 5/2

x = √(5/2)

x = √5/√2

Rationalizing the denominator;

x = (√2 * √5)/(√2 * √2)

x = √10/2

4 0
3 years ago
HELP ME PLEASE!
Delicious77 [7]
Sounds as tho' you have an isosceles triangle (a triangle with 2 equal sides).  If this triangle is also a right triangle (with one 90-degree angle), then the side lengths MUST satisfy the Pythagorean Theorem.

Let's see whether they do.

8^2 + 8^2 = 11^2  ???
 64    + 64 = 121?  NO.  This is not a right triangle.

If you really do have 2 sides that are both of length 8, and you really do have a right triangle, then:

8^2 + 8^2 = d^2, where d=hypotenuse.  Then 64+64 = d^2, and 

d = sqrt(128) = sqrt(8*16) = 4sqrt(8) = 4*2*sqrt(2) = 8sqrt(2) = 11.3.

11 is close to 11.3, but still, this triangle cannot really have 2 sides of length 8 and one side of length 11.
7 0
3 years ago
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