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Anvisha [2.4K]
3 years ago
7

Jared said that every prime number is an integer. Do you agree or disagree

Mathematics
1 answer:
Nookie1986 [14]3 years ago
7 0
I "agree." This statement is correct every <span>prime number is an integer. Integers are </span><span>a whole number and a number that is not a fraction. Prime numbers cant be fractions therefore every prime number is in fact a integer.

Hope this helps!
</span>
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sesenic [268]
Exponent way n
exponetional way
6 0
3 years ago
I have 8 questions witch means 80 points answer correctly!
kolezko [41]
<h3>Answer : </h3>

\Large \pink{\tt \dfrac{35}{36}}

<h3>Solution :</h3>

\tt \dfrac{3}{4} + \dfrac{2}{9}

By taking LCM = 4 × 9 = 36

\tt = \dfrac{3 \times 9}{4 \times 9} + \dfrac{2 \times 4}{9 \times 4}

\tt = \dfrac{27}{36} + \dfrac{8}{36}

\tt = \dfrac{27 + 8}{36}

\tt = \dfrac{35}{36}

\pink{\tt \therefore \: Answer \: is \: \dfrac{35}{36}}

7 0
3 years ago
2(x - 2.6) + 2.91 = 7.71
Gennadij [26K]

I'll show a step-by-step. I'm not in the mood to explain right now lol.

2(x-2.6)+2.91=7.71

2x-5.2+2.91=7.71

   +5.20          +5.20

2x+2.91=12.91

    -2.91  -2.91

2x=10

/2   /2

x=5

---

hope it helps

sorry if it doesn't

3 0
3 years ago
What are the vertical asymptote(s) of y= (x-6)/(x+8) (x-7)
White raven [17]

Answer:

x = -8 and x= 7

Step-by-step explanation:

recall that for a rational expression, the vertical asymptotes occur at x-values that causes the expression to become undefined. These occur when the denominator becomes zero.

Hence the asymptototes will occur in x-locations where the denominator , i.e

(x+8)(x-7) = 0

solving this, we get

(x+8) = 0 ----> x = -8

or

(x-7) = 0 ------> x = 7

hence the asymptotes occur x = -8 and x= 7

5 0
3 years ago
Read 2 more answers
Find the equation of the line that passes through (-1,2) and is perpendicular to
Natalija [7]

Answer:

Remember that the slope of perpendicular lines are negative reciprocals of each other.

Step-by-step explanation:

y = 1 - 2x     the slope is -2     the value of the x term.

So the slope of the new line using point (- 1, 2)  is  1/2.

Now use y = mx + b where y = -1, x = 2, and m = 1/2 .

y = mx + b

-1 = 1/2(2) + b                solve for "b", the y-intersect

-1 =  1 + b

-2 = b

The line that is perpendicular to y = 1 - 2x  is  y = 1/2x - 2

8 0
2 years ago
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