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Citrus2011 [14]
2 years ago
8

Determine the standard form of the equation of the line that passes through (-7, 8) and (0, 2)

Mathematics
1 answer:
Vlad [161]2 years ago
6 0

Answer:

y=-0.857x+2

Step-by-step explanation:

Attached image

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What is the value of y?
slega [8]

Answer:

p

Step-by-step explanation:

3 0
2 years ago
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Part I
Crazy boy [7]

Answer:

130

Step-by-step explanation:

10 x 13 = 130

13 + 13 + 13 + 13 + 13 + 13 + 13 + 13 + 13 + 13 = 130

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3 years ago
Y=25x+35
kow [346]

Answer:

The equation is in the form y=mx+b, where m=slope, b=y-intercept.

The y-intercept is 35: so the line goes through the y-axis at (0,35).

The slope is 25: so we need to count out the slope as rise over run, or 25 up and 1 to the right, starting from the y-intercept.

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Five times the sum of a number and three is the same as three times the difference of twice the number and one what is the numbe
cupoosta [38]

Answer:

the number is 105

Step-by-step explanation:

5(x+3) = 3(2x - 1)

5x + 15 = 6x - 3

15 = 1x - 3  

(15 + 3)

x = 18

3 0
2 years ago
If f(x) = x + 7 and g(x) = 1 / x - 13, whaf is the domain of (f°g)(x)?​
ZanzabumX [31]

Answer: Choice D) x can be anything but 13

========================================================

Explanation:

The domain of (f \circ g)(x) = f(g(x)) is the same as the domain of g(x)

The domain for g(x) is \{x|x \ne 13\} saying we can plug in any number we want as long as it's not 13. This is to avoid dividing by zero. The same domain applies for the composite function because

f(x) = x+7\\\\\\f(g(x)) = g(x)+7\\\\\\f(g(x)) = \frac{1}{x-13}+7\\\\\\(f \circ g)(x) = \frac{1}{x-13}+7\\\\\\

and we can see that we still need to kick out x = 13 from the domain to avoid the division by zero issue.

6 0
2 years ago
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