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maxonik [38]
3 years ago
11

7x-8(-2x+9)=112 What is x

Mathematics
2 answers:
zaharov [31]3 years ago
8 0
Okay so first you need to combine like terms 
alex41 [277]3 years ago
3 0
 (8, -2) here is your answer

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Inverse of the function h(x)=\dfrac{3}{2}(x-11)h(x)= 2 3 ​ (x−11)h, left parenthesis, x, right parenthesis, equals, start fracti
blagie [28]

Answer:

The inverse function of h(x) = 3/2*(X-11)  is:  g(x)= (2/3*X) +11

Step-by-step explanation:

h(x) = Y= 3/2*(X-11)

To find the inverse function, the first step is to exchange the position of the variables with each other. So;

X= 3/2*(Y-11)

Now we need to isolate the variable Y from this equation. The final result will be te inverse function.

X=3/2*(Y-11)

2*X=3*(Y-11)

2/3*X=Y-11

2/3*X +11 = Y

Y= (2/3*X) + 11  (Inverse function)

5 0
3 years ago
Read 2 more answers
Would appreciate the help ! ​
aleksandr82 [10.1K]

This is one pathway to prove the identity.

Part 1

\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{1}{\tan(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\cot(\theta) = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{\cos(\theta)}{\sin(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)*\sin(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)(1-\cos(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\

Part 2

\frac{\sin^2(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)-\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-(\cos(\theta)-\cos^2(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-\cos(\theta)+\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\

Part 3

\frac{\sin^2(\theta)+\cos^2(\theta)-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1}{\sin(\theta)} = \frac{1}{\sin(\theta)} \ \ {\checkmark}\\\\

As the steps above show, the goal is to get both sides be the same identical expression. You should only work with one side to transform it into the other. In this case, the left side transforms while the right side stays fixed the entire time. The general rule is that you should convert the more complicated expression into a simpler form.

We use other previously established or proven trig identities to work through the steps. For example, I used the pythagorean identity \sin^2(\theta)+\cos^2(\theta) = 1 in the second to last step. I broke the steps into three parts to hopefully make it more manageable.

3 0
2 years ago
The Circle with a center (10,1) and the radius 5 has equation
liberstina [14]
<h3>Answer:  (x-10)^2 + (y-1)^2 = 25</h3>

============================================

Explanation:

The general template of a circle is

(x-h)^2 + (y-k)^2 = r^2

Where,

  • (h,k) is the center
  • r is the radius

We are given (10,1) as the center so (h,k) = (10,1) meaning that h = 10 and k = 1 pair up together.

r = 5 is the given radius.

-----

Plug the values h = 10, k = 1, r = 5 into the equation to get:

(x-h)^2 + (y-k)^2 = r^2

(x-10)^2 + (y-1)^2 = 5^2

(x-10)^2 + (y-1)^2 = 25

5 0
3 years ago
A die was rolled 10 times and 2 appeared 4 times. What is the probability of getting 2?
fiasKO [112]

Answer:

none of the above

Step-by-step explanation:

probability shouldn't be equal to or greater than 1

5 0
2 years ago
What is the answer h+6\5=2
nexus9112 [7]

Answer:

h = 4/5

Step-by-step explanation:

h + (6/5) = 2

h = 2 - (6/5)

h = (10/5) - (6/5)

h = (10-6)/5

h = 4/5

Check:

(4/5) + (6/5) = 2

10/5 = 2

8 0
3 years ago
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