h(t) = -16t² + 50t + 5
The maximum height is the y vertex of this parabola.
Vertex = (-b/2a, -Δ/4a)
The y vertex is -Δ/4a
So,
The maxium height is -Δ/4a
Δ = b² - 4.a.c
Δ = 50² - 4.(-16).5
Δ = 2500 + 320
Δ = 2820
H = -2820/4.(-16)
H = -2820/-64
H = 2820/64
H = 44.0625
So, the maxium height the ball will reach is 44.0625
Answer:
The answer is x=10
Step-by-step explanation:
The mountain climber has travelled 75 feet below sea level while descending down a cliff.
Given:
- A mountain climber at sea level starts descending down a cliff.
- Her location can be represented by -75 ft.
To find:
The distance travelled by a mountain climber.
Solution
- Distance ascending above sea level is taken in a positive direction.
- Distance descending down sea level is taken in a negative direction.
- This negative and positive only represents the direction
The location of mountain climber after descending from cliff = -75 ft
The distance covered by the mountain climber = 75 ft
The mountain climber has travelled 75 feet below sea level while descending down a cliff.
Learn more about descending and ascending here:
brainly.com/question/1477877?referrer=searchResults
brainly.com/question/108740?referrer=searchResults
Answer:
Since I cant say which answer due to no graph, I'll tell you How to do so.
Step-by-step explanation:
if it is A, then the there is at least one angle or line length that is not the same. To find the area of a grided shape, use the traingle theorm of a^2+b^2=c^2.
if it is B, that meants moving the shape to the other will result in a perfect fit. Be sure to find if all side lengths are the same as that means that the shape IS congrouent, as equal side length means equal angles. However, it will not be this choice if the shape is mirrored to the other
A rotation and tranlastion means it is flipped either upside down or up and moved to the shape.
D, a reflection, which means its the opposite. Like a mirrored shape. Then you move it.
640×3= 1,920 Then you don't need to estimate it since it's estimated.
hope this helps :-)<span />
