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expeople1 [14]
3 years ago
11

Select the correct answer. Shape 1 and shape 2 are plotted on a coordinate plane. Which statement about the shapes is true? A. S

hape 1 and shape 2 are not congruent. B. A translation will prove that shape 2 is congruent to shape 1. C. A rotation and a translation will prove that shape 2 is congruent to shape 1. D. A reflection, a rotation, and a translation will prove that shape 2 is congruent to shape 1.
Mathematics
1 answer:
IceJOKER [234]3 years ago
6 0

Answer:

Since I cant say which answer due to no graph, I'll tell you How to do so.

Step-by-step explanation:

if it is A, then the there is at least one angle or line length that is not the same. To find the area of a grided shape, use the traingle theorm of a^2+b^2=c^2.

if it is B, that meants moving the shape to the other will result in a perfect fit. Be sure to find if all side lengths are the same as that means that the shape IS congrouent, as equal side length means equal angles. However, it will not be this choice if the shape is mirrored to the other

A rotation and tranlastion means it is flipped either upside down or up and moved to the shape.

D, a reflection, which means its the opposite. Like a mirrored shape. Then you move it.

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The plant grew 1.5 cm each day.
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Two forces with magnitudes of 90 and 50 pounds act on an object at angles of 30° and 160°, respectively. Find the direction and
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Force 1, F1 = 90, angle 30°

Force 2, F2 = 50, angle 160°

F1 = 90 cos(30) i + 90 sin (30) j
F2 = 50 cos (160) i + 50 sin (160) j

F1 = 90*0.866 i + 90*0.5 j
F2 = 50*(- 0.940) i + 50*0.342 j

F1 = 77.94 i + 45 j
F2 = -47 i +17.10 j

Resultant force, Fr = F1 + F2

Fr = [77.94 - 47.00] i +[45 +17.10]j = 30.94 i + 62.10 j

Magnitude = √[30.94 ^2 + 62.10^2] = 69.38 pounds

Direction  = arctan[62.10/30.94] = 63.52 °


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3 years ago
What is the quotient (2x^3 + 3x - 22) / (x-2)
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Step-by-step explanation:

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3 years ago
$43 dinner 18% gratuity
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So you want to know how much was paid in total?

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The mean annual salary for intermediate level executives is about $74000 per year with a standard deviation of $2500. A random s
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Answer:

11.51% probability that the mean annual salary of the sample is between $71000 and $73500

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 74000, \sigma = 2500, n = 36, s = \frac{2500}{\sqrt{36}} = 416.67

What is the probability that the mean annual salary of the sample is between $71000 and $73500?

This is the pvalue of Z when X = 73500 subtracted by the pvalue of Z when X = 71000. So

X = 73500

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{73500 - 74000}{416.67}

Z = -1.2

Z = -1.2 has a pvalue of 0.1151

X = 71000

Z = \frac{X - \mu}{s}

Z = \frac{71000 - 74000}{416.67}

Z = -7.2

Z = -7.2 has a pvalue of 0.

0.1151 - 0 = 0.1151

11.51% probability that the mean annual salary of the sample is between $71000 and $73500

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2 years ago
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