First, look at the digits less than one one-hundredth (

, or .01):
0.00416
See if that number is closer to the higher or lower hundredth:
(if the first digit is 5 or greater, then higher;
if the first digit is 4 or lower, then lower)
Since 4 is closer to the lower hundred, round down
0.00416 -> 0.00000
Add this to the digits we didn't touch:
<span>17,546.32000 + 0.00000 = 17,546.32
</span>17,546.32416 rounded to the nearest hundredth is
C. <span>
17,546.32</span>
Answer:
i attatched a picture of how it should look
Step-by-step explanation:
Answer:
Step-by-step explanation:
<u>Given function:</u>
<u>Putting this into slope-intercept form: y = mx + b</u>
- 9x + 3y = 12
- 3y = -9x + 12
- y = -3x + 4
<u>Replacing y with f(x)</u>
Factor:
3x^2 + 27
= 3(x^2 + 9)
Answer is 3(x^2 + 9), when factored.
A) (3x + 9i)(x + 3i)
= (3x + 9i)(x + 3i)
= (3x)(x) + (3x)(3i) + (9i)(x) + (9i)(3i)
= 3x^2 + 9ix + 9ix + 27i^2
= 27i^2 + 18ix + 3x^2
B) (3x - 9i)(x + 3i)
= (3x + - 9i)(x + 3i)
= (3x)(x) + (3x)(3i) + ( - 9i)(x) + (- 9i)(3i)
= 3x^2 + 9ix - 9ix - 27i^2
= 27i^2 + 3x^2
C) (3x - 6i)(x + 21i)
= (3x + - 6i)(x + 21i)
= (3x)(x) + (3x)(21i) + (- 6i)(x) + ( -6i)(21i)
= 3x^2 + 63ix - 6ix - 126i^2
= - 126i^2 + 57ix + 3x^2
D) (3x - 9i)(x - 3i)
= (3x + - 9)(x + - 3)
= (3x)(x) + (3x)( - 3i) + (- 9)(x) + ( - 9)( - 3i)
= 3x^2 - 9ix - 9x + 27i
= 9ix + 3x^2 + 27i - 9x
Hope that helps!!!
Answer:
A i think
Step-by-step explanation: