Answer:
Hey u want to join a meet and we can help u out I swear it's going to be fun yzn-dggf-jcq
L=7+W
area=30=LW
so subsitute 7+W for length
30=(7+W)(W)
30=W²+7W
minus 30 both sides
0=W²+7W-30
factor
what 2 numbers multiply to get -30 and add to get 7
-3 and 10
0=(W-3)(W+10)
set to zero
0=W-3
3=W
0=W+10
-10=W
false, can't have a negative width
width=3in
L=7+W
L=7+3
L=10
the length is 10in
the width is 3in
<span>Equation at the end of step 1 :</span><span> (((x3)•y)-(((3x2•y6)•x)•y))-6y = 0
</span><span>Step 2 :</span><span>Step 3 :</span>Pulling out like terms :
<span> 3.1 </span> Pull out like factors :
<span> -3x3y7 + x3y - 6y</span> = <span> -y • (3x3y6 - x3 + 6)</span>
Trying to factor a multi variable polynomial :
<span> 3.2 </span> Factoring <span> 3x3y6 - x3 + 6</span>
Try to factor this multi-variable trinomial using trial and error<span>
</span>Factorization fails
<span>Equation at the end of step 3 :</span><span> -y • (3x3y6 - x3 + 6) = 0
</span><span>Step 4 :</span>Theory - Roots of a product :
<span> 4.1 </span> A product of several terms equals zero.<span>
</span>When a product of two or more terms equals zero, then at least one of the terms must be zero.<span>
</span>We shall now solve each term = 0 separately<span>
</span>In other words, we are going to solve as many equations as there are terms in the product<span>
</span>Any solution of term = 0 solves product = 0 as well.
Solving a Single Variable Equation :
<span> 4.2 </span> Solve : -y = 0<span>
</span>Multiply both sides of the equation by (-1) : y = 0
Interval notation: [-2,3]