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Arlecino [84]
3 years ago
9

What is the area of a sector with radius 6" and measure of arc equal to 120°?

Mathematics
1 answer:
fenix001 [56]3 years ago
7 0
The area of a sector = 0.5 * radius^2 * central angle measure (in radians)

So that:

Area_{sector}=  \frac{1}{2} * 6^2* \frac{120}{180}*\pi=12\pi=37.69911
\\
Area_{sector}=37.7 sq in

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NEED HELP QUICK!! :)
Vlada [557]
Let x and y be your two consecutive whole numbers

x < sqrt(142) < y
x^2 < 142 < y

So, we are looking for x and y such that x^2 < 142 and y^2 > 142.

The closest squared number to 142 is 144 = 12^2.
Next is 11^2 = 121.

11 and 12 are consecutive.

11^2 = 121 < 142 < 144 = 12^2

Thus, 11 and 12 are your numbers

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3 years ago
Can someone give me a fake band name???
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Answer:

loaded diper

Step-by-step explanation:

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Choose the simplest form of this fraction
Shkiper50 [21]
The correct answer is 2 1/7
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3 years ago
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Answer:

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Step-by-step explanation:

3 0
3 years ago
From the side of a hill wai-kin looks up at the top of a nearby vertical cliff at an angle of elevation of 36 degrees and looks
oksano4ka [1.4K]

Answer:

881.5 meters.

Step-by-step explanation:

The horizontal plane at the level of wai-kin's eyes divide the height of the cliff into two parts. Let the upper part be represented by x and the lower part be represented by y.

The height of the cliff = x + y

Applying the appropriate trigonometry functions.

To determine the value of x;

Tan θ = \frac{opposite}{adjacent}

Tan 36^{o} = \frac{x}{490}

⇒ x = 490 x Tan 36^{o}

      = 490 x 0.7265

     = 355.985

x = 356 meters

To determine the value of y;

Tan θ = \frac{opposite}{adjacent}

Tan 47^{o} = \frac{y}{490}

⇒ y = 490 x Tan 47^{o}

      = 490 x 1.0724

      = 525.476

y = 525.5 meters

Therefore,

The height of the cliff = x + y

                                   = 355.985 + 525.476

                                   = 881.461

The height of the cliff is 881.5 meters.

3 0
3 years ago
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