We can use linear combinations of the equations to eliminate variables.
3x - 4y = 1
-2x + 3y = 1
To eliminate y we'll make the linear combination of 3 times the first equation minus four times the second.
9x - 12y = 3
-8x + 12y = 4
Adding,
x = 7
We could solve for y directly but let's use another linear combination, twice the first plus three times the second:
2(3x - 4y) + 3(-2x + 3y)= 2(1)+3(1)
y = 5
Check: 3(7)-4(5)=1 good. -2(7)+3(5)=1 good.
Q18 Answer: (7,5)
y = -3x + 5
5x - 4y = -3
4y +1(5x - 4y) = 4(-3x + 5) + 1(-3)
5x = -12x + 20 -3
17 x = 17
x = 1
y = -3(1) + 5 = 2
Check: 5(1) - 4(2) = -3 good
Q19 Answer (1,2)
6x + 5y = 25
x = 2y + 24
6x = 12y + 144
5y = 25 - 12y - 144
17y = -119
y = -119/17= -7
x = 2y+24= 10
Check: 6(10)+5(-7)=25 good 2y+24=2(-7)+24=10=x good
Q20 Answer (10,-7)
3x + y = 18
-7x + 3y = -10
9x + 3y = 54
9x - -7x = 54 - -10
16x = 64
x=4
y = 18 -3x = 18-12=6
Check: 3(4)+6=18 good, -7(4)+3(6)=-10 good
Q21 Answer: (4,6)
Order.
9, 12, 12, 14, 15, 16, 18, 21
Now split into quarters.
9, 12, 12, 14, 15, 16, 18, 21
| | |
(1) (3)
Determine the values of (1) and (3) by using medians.
14 + 12 + 12 + 9 / 4
47 / 4
approx. 12
So Q1 = 12.
15 + 16 + 18 + 21 / 4
70 / 4
approx. 17
Therefore the answer is C I think. I have not done this ever before. All the knowledge I did was from research lol
If one of our zeros is 4, then the factor is x-4. If the second zero is 5i, then the conjugate root theorem says there HAS to be a root that is -5i. So our 3 factors are (x-4)(x+5i)(x-5i). We will FOIL out these factors to get the polynomial. Let's start with the ones that contain the imaginary numbers. Doing that mutliplication we get x^2-25i^2. i^2 is equal to -1, so what that expression simplifies down to is

. Now we will multiply in that last factor of (x-4):

. FOILing out we have

. There you go!
9514 1404 393
Answer:
(-2, 2)
Step-by-step explanation:
The orthocenter is the intersection of the altitudes. The altitude lines are not difficult to find here. Each is a line through the vertex that is perpendicular to the opposite side.
Side XZ is horizontal, so the altitude to that side is the vertical line through Y. The x-coordinate of Y is -2, so that altitude has equation ...
x = -2
__
Side YZ has a rise/run of -1/1 = -1, so the altitude to that side will be the line through X with a slope of -1/(-1) = 1. In point-slope form, the equation is ...
y -(-1) +(1)(x -(-5))
y = x +4 . . . . . . . . subtract 1 and simplify
The orthocenter is the point that satisfies both these equations. Using the first equation to substitute for x in the second, we have ...
y = (-2) +4 = 2
The orthocenter is (x, y) = (-2, 2).
Answer:Said Imneverlackin'alwayspistolpacking
Withthemautomaticswegonsendhimtoheaven
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Step-by-step explanation: