Answer:2
Step-by-step explanation:
Combine like terms and divide
8x/4x
2
Find the zeros<span> of Function (</span>x)= (x+3)^2(x-5)^6 and state the multiplicity. ... (x--5)^6<span> = 0=> </span>x--5<span>= 0 => </span>x<span> = </span>5<span>. Therefore real </span>zero's of the function<span> are --</span>3<span>,5.</span><span />
9514 1404 393
Answer:
yes
Step-by-step explanation:
The given line of reflection is a perpendicular bisector of every segment joining any figure point with its image. Hence the given image trapezoid is a reflection across the line of the given pre-image trapezoid.
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For example, Line f is the perpendicular bisector of AA'.
The answer is 10 because you subtract 17-7
The answer is x=29
I hope this helps you
