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sineoko [7]
3 years ago
13

HELP I WILL GIVE BRAINLIEST

Mathematics
1 answer:
ddd [48]3 years ago
4 0
False because it is only showing the quarter
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Please help me, question is the picture
Hitman42 [59]
The answer is 425 miles.

Both of the companies can be represented by an equation. The first company being f(a) and the second company bring f(b).
f(a)=$0.06x+65
f(b)=$0.10x+48
We want to find where they are equal, so we can set the equations equal to each other.
$0.06x+65=$0.10x+48
From here we can simplify the equation.
17=$0.04x
425=x
8 0
3 years ago
Read 2 more answers
–x – 7 = 16 please help me
atroni [7]
Move the -7 to the right, its sign will flip (do you know why?)
Negate both sides to change -x to x

-x = 16+7
-x = 23
x = -23
7 0
3 years ago
Read 2 more answers
Does this table represent a proportional relationship?<br><br> A) Yes<br> B) No
Nonamiya [84]

Answer:

a

Step-by-step explanation:

it is all doubles

7 0
3 years ago
Read 2 more answers
7. Veronica is choosing between two health clubs.
vesna_86 [32]

Answer:

The total cost for  each health club will be the same after 4 months.

Step-by-step explanation:

  • Let A = membership fee for studio A
  • B = membership fee for studio B
  • x= membership month

  • A = 22 + 24.5x
  • B = 47.00 + 18.25x

We want to when the total cost at each health studio is the same.

In other words, when A = B.

Therefore, the expression becomes

A = B

22\:+\:24.5x=47.00\:+\:18.25x

Step 1: Simplify both sides of the equation.

24.5x+22=18.25x+47

Step 2: Subtract 18.25x from both sides.

24.5x+22-18.25x=18.25x+47-18.25x

6.25x+22=47

Step 3: Subtract 22 from both sides.

6.25x+22-22=47-22

6.25x=25

Step 4: Divide both sides by 6.25

\frac{6.25x}{6.25}=\frac{25}{6.25}

x=4

Therefore, the total cost for  each health club will be the same after 4 months.

8 0
2 years ago
Given the function f(x) = 3x + 1, what is the value of f(9)
Aliun [14]

f(x) = 3x + 1

f(9) = 3(9) + 1

f(9) = 27 + 1

f(9) = 28

f(9) = 28. I hope this helps! I have a g00gle classroom where I help with algebra including this. If you are interested, please consider joining. I will post the class code in the comments if it would let me. Sorry it wouln't let me type g0ogle properly.

4 0
3 years ago
Read 2 more answers
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