Answer:

Step-by-step explanation:
The given relation is

To make
the subject, we square both sides of the equation to get;


Isolate
on one side of the equation;

Or

We take the positive square root of both sides to get;

It passes through the center of the points. (2)
When doing a line of best fit, you want the line to have equal number of points on either side of the line.
Answer:






Step-by-step explanation:
For each toss, there are only two possible outcomes. Either it is tails, or it is not. The probability of a toss resulting in tails is independent of any other toss, which means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
Fair coin:
Equally as likely to be heads or tails, so 
5 tosses:
This means that 
Probability distribution:
Probability of each outcome, so:







Answer:
1080
___ rode a plane for 5^2 miles on a flight to ___. She then took a flight to ___ which was 5^4 miles. How much further did she fly on the second flight?
you can decide where she went and what her name was.
Step-by-step explanation:
6^3 = 213
6^4 = 1296
1296 - 216 = 1080