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AleksandrR [38]
3 years ago
10

The list of multiples for 6 is infinite. True or False?

Mathematics
2 answers:
Vaselesa [24]3 years ago
6 0

Answer:

True; yes.

Step-by-step explanation:

Think about it, what does <em>etc, etc </em>mean? It means repetitive-a pattern, in a sort of way. So here are some multiples of 6:

6,12,18,24,30,36,42,48,54,60,66,72,78,84,90,96,102,108,114,120,126,132,138,144,150,156,162,168,174,180,186,192,198,204,210,216,222,228,234,240,246,252,258,264,270,276,282,288,294,  etc.

As you can see, all I'm doing is adding 6 to every step I go. So when you say there is an infinite number, then these multiples are going to be infinite.

IgorC [24]3 years ago
4 0

Answer:

True

Step-by-step explanation:

As there are infinite numbers, the list of multiples are also infinite.

Multiples of 6 : 6, 12 , 18 , 24 ..............

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Answer:

Fraction of the original board left = \frac{2}{15}

Step-by-step explanation:

Let the length of the board is = l feet

Marty saws off \frac{1}{5} of a wooden board.

Length of the board left = l - (\frac{1}{5})l

                                        = (\frac{4}{5})l feet

He saws off \frac{3}{4}th of the remaining board,

Board left = (\frac{4}{5})l-[(\frac{4}{5})l\times (\frac{3}{4})]

                = \frac{4}{5}l-\frac{3}{5}l

                = \frac{1}{5}l feet

He finally saws off \frac{1}{3}rd of the remaining board.

Board left = \frac{1}{5}l-[\frac{1}{5}\times \frac{1}{3}]l

                = (\frac{1}{5}-\frac{1}{15})l

                = \frac{2}{15}l feet

Fraction of the original board left = \frac{\frac{2}{15}l}{l}

                                                       = \frac{2}{15}

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FromTheMoon [43]

Answer:

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Step-by-step explanation:

Here we are required to find the distance between two coordinates. We will use the distance formula to find the distance

The distance formula is given as

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Here we are given two coordinates as

(6,5\sqrt{5} ) , (4,3\sqrt{2} )

Substituting these values in the Distance formula given above we get

D=\sqrt{(6-4)^2+(5\sqrt{5} -3\sqrt{2}) ^2}

D=\sqrt{(2)^2+(5\sqrt{5})^2+(3\sqrt{2})^2-2*5\sqrt{5}*3\sqrt{2}}\\

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Hence this is our answer

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